2019-04-14 14:41:27 8 Comments

Harmonic analysis is concentrated mostly on studying locally compact groups. I would like to ask people about examples of **non-locally compact topological groups** that are interesting in connection with some applications in mathematics (or physics). I must confess that I know only two examples:

topological vector spaces are studied as examples of topological groups (with the additive group operation) to which Pontryagin duality is sometimes transferred from the class of locally compact abelian groups,

the groups of diffeomorphisms of smooth manifolds are studied in the theory of infinite dimensional manifolds.

Can people enlighten me about other similar subjects? (If possible, with motivations.)

### Related Questions

#### Sponsored Content

#### 0 Answered Questions

### Interior of fundamental domains of lattices in locally compact groups

**2018-09-07 21:40:05****Ulrik****62**View**3**Score**0**Answer- Tags: harmonic-analysis topological-groups

#### 0 Answered Questions

### Best constant for maximal function for locally compact groups

**2016-12-28 17:52:58****BigM****283**View**3**Score**0**Answer- Tags: reference-request fa.functional-analysis harmonic-analysis topological-groups

#### 0 Answered Questions

### Laplace Transform in the context of Gelfand/Pontryagin

**2014-02-11 14:23:22****Greg Zitelli****630**View**14**Score**0**Answer- Tags: fa.functional-analysis fourier-analysis harmonic-analysis fourier-transform laplace-transform

#### 1 Answered Questions

### [SOLVED] Wiener algebra for nonabelian locally compact groups

**2014-08-03 10:36:43****Evan DeCorte****268**View**3**Score**1**Answer- Tags: reference-request harmonic-analysis

#### 0 Answered Questions

### Tauberian measures on a locally compact abelian group

**2013-09-15 18:09:30****M.González****126**View**1**Score**0**Answer- Tags: fa.functional-analysis harmonic-analysis

#### 1 Answered Questions

### [SOLVED] An example for the Convolution on not compact topological groups

**2013-08-07 07:24:23****hassan zaki****130**View**1**Score**1**Answer- Tags: harmonic-analysis

#### 1 Answered Questions

### [SOLVED] Matched pair of locally compact groups

**2013-07-20 19:05:01****Sutanu****133**View**3**Score**1**Answer- Tags: fa.functional-analysis harmonic-analysis

#### 1 Answered Questions

### [SOLVED] Finite index subgroups of locally compact groups

**2013-06-05 22:25:12****user23860****428**View**3**Score**1**Answer- Tags: harmonic-analysis gr.group-theory

#### 1 Answered Questions

### [SOLVED] Locally Compact Quantum Groups application

**2012-10-16 23:46:55****zora****472**View**12**Score**1**Answer- Tags: harmonic-analysis oa.operator-algebras

#### 2 Answered Questions

### [SOLVED] Fourier Transform on Locally compact quantum groups

**2012-05-31 01:43:56****Zora****688**View**4**Score**2**Answer- Tags: harmonic-analysis quantum-groups fa.functional-analysis

## 6 comments

## @Nik Weaver 2019-04-15 20:10:29

The question mentions topological vector spaces, but aren't Banach spaces a special case of sufficient interest to merit explicit mention? Every infinite dimensional Banach space is a non-locally compact topological group under addition and the norm topology.

## @Peter Michor 2019-04-15 19:13:21

Quantum mechanics: The unitary group $U$ of a Hilbert space. If you use the norm topology, then it is a Banach Lie group with bounded skew hermitian operators as Lie algebra. But unbounded self-adjoint operators $A$ (Schrödinger operators) lead to 1-parameter semigroups $e^{itA}$ in $U$, where now the strong operator topology plays a role.

## @André Henriques 2019-04-16 05:48:00

Some relevant facts about $U(H)$ in its strong operator topology (SOT) can be found here: arxiv.org/abs/1309.5891. In particular it is a topological group (as explained in the linked paper, a number of prominent references explicitly state that $(U(H),$SOT$)$ is not a topological group!). More precisely, it is a Polish group. Even more, when restricted to $U(H)\subset B(H)$, the strong operator topology, the weak operator topology, the ultra-strong topology, the ultra-weak topology, and the compact open topology all agree.

## @Tom Goodwillie 2019-04-15 15:26:29

This is far from the use of topological groups in analysis, but:

In homotopy theory a basic background fact that is that a (based connected) space is always the classifying space of a topological group. In a little more detail: the following four categories (with suitable notions of weak homotopy equivalence) are equivalent for purposes of homotopy theory.

So in some sense arbitrary topology groups play a role in homotopy theory.

In practice homotopy-theorists work with 2 as a substitute for 1, and with 3 as a tool for 2, but 4 is part of the picture. Roughly speaking, the topological group associated with a based space $X$ is the space of based loops in $X$, but in order to represent this homotopy type by an actual topological group one ordinarily goes through simplicial groups.

## @Nate Eldredge 2019-04-15 15:06:52

A couple of common classes of examples you may have overlooked:

The rationals $\mathbb{Q}$ with their usual topology. More generally, any non-closed subgroup of a locally compact Hausdorff group will be a non-locally compact group (in its subspace topology). There are lots of situations where it's convenient to prove something about a locally compact group by working on a dense subgroup.

Infinite products of non-compact groups with their product topology. Some of these are topological vector spaces like $\mathbb{R}^\omega$, but for instance, $\mathbb{Z}^\omega$ is another simple example (it's homeomorphic to Baire space, and to the set of irrationals in $\mathbb{R}$). Products arise naturally any time you want to say "give me a whole sequence of these". The failure of such groups to have a Haar measure is a frequent sticking point in analysis and probability.

## @Sergei Akbarov 2019-04-15 19:30:59

Nate, to tell the truth, I don't understand how can separating $\mathbb Q$ from $\mathbb R$ be useful if the topology is preserved.

## @LSpice 2019-04-15 19:50:13

@SergeiAkbarov, perhaps you might ask a number theorist …?

## @Francois Ziegler 2019-04-15 04:46:51

## @Sergei Akbarov 2019-04-15 05:09:37

Francois, could you, please, say a few words on where this is used?

## @Francois Ziegler 2019-04-15 06:05:30

@SergeiAkbarov As with all groups, one studies their homogeneous symplectic manifolds, resp. (projective) unitary representations as potential models of classical, resp. quantum systems. Pressley-Segal (1986, introduction) cite some such successes, but beyond that I see mainly hope and

l’art pour l’artfun...## @R W 2019-04-14 15:06:58

There are two quite popular areas related to "big" or "large" groups. One concerns extreme amenability and fixed point properties (see Pestov), and the other concerns harmonic analysis and the representation theory (see Borodin - Olshanski).

## @Sergei Akbarov 2019-04-14 17:08:25

R W as far as I can see, they change the definition of topological group. In their considerations the operation of multiplication should not be jointly continuous, but separately continuous, is it?

## @R W 2019-04-14 17:32:04

@Sergei Akbarov - Where do you see this?

## @Sergei Akbarov 2019-04-14 18:13:46

In the paper by Vladimir Pestov: the multiplication in $U(\ell^2)$ is separately continuous with respect to the pointwise convergence, not jointly.

## @user95282 2019-04-14 18:17:06

@Sergei Akhbarov The multiplication in the unitary group is jointly continuous in the operator topology.

## @Sergei Akbarov 2019-04-14 18:24:38

Ah, yes! Because $||A||=1$ for all $A\in U(\ell^2)$ (you mean in the strong operator topology). Excuse me, I confused this with the group of all invertibe elements.

## @user95282 2019-04-14 19:38:27

@Sergei Akhbarov Weak or strong operator topology, either way. It's the same topology on $U(\ell^2)$.

## @Sergei Akbarov 2019-04-14 19:40:54

@user95282 yes, ok! You said they study representations of $U(\ell^2)$?

## @user95282 2019-04-14 20:35:00

@Sergei Akhbarov Not so much representations of $U(\ell^2)$, but group representations in $U(\ell^2)$. See G.W. Mackey, Bull AMS 3,1 (1980) 543-698.

## @André Henriques 2019-04-16 21:42:18

@Sergei Akbarov: See my comment to Peter Michor's answer.

## @Sergei Akbarov 2019-04-17 02:29:18

@AndréHenriques thank you, I already printed this article, it's useful!