2014-04-18 11:12:35 8 Comments

Everyone calls the centrifugal force a pseudo force and claims that it is not really present, even though there are so many machines listed as taking advantage of it (e.g. centrifuge, washing machine, drier). It also has the same magnitude as the centripetal force, so that they cancel each other out but I can definitely feel it every time I take a sharp turn in a car.

So can you explain whether the centrifugal force is real?

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## 5 comments

## @Vektroid 2016-07-09 08:32:41

Centrifugal force is not considered as a real force in any standard terms, but it may be used to measure resultant forces or reactions in a situation in an easier way. Like what @AJMansfield said, you could use it as a 'correction force', just like how you use Gravity!

Theoretically, no, it is not real.

Depending on the situation, it may be felt and experienced, but in another situation it may not be seen at all. To someone in a merry-go-round it's real, to an observer it is not.

If you wish to state Centrifugal force in a research paper or anything that can be read and criticized, then i recommend stating what is experiencing the force first, or miscommunication may happen which will mark you down.

## @Frank Smith 2016-02-11 15:57:58

In a rotating system such as a ball swung on a piece of string your hand exerts an inward radial centripetal force on the ball, this is the force that causes the ball to rotate. The ball, in its turn, exerts an outward radial force on your hand. Both forces are real. The ball is "Exerting" a centrifugal force, it is not subject to such a force. Release the string and the ball will fly off tangentially due to its momentum, it will not fly outwards radially due to a centrifugal force. Any decent book on physics will confirm this. Go to www.jottit.com/6fyk for more info

## @AJMansfield 2014-04-19 01:44:31

A pseudoforce, like centrifugal force, the Coriolis force, or gravity, is a correction term we use in order to be able to apply standard physical models to accelerating reference frames, when the alternatives (rotational motion, rotation in 3-space, or relatativity) are conceptually or computationally harder to deal with.

Imagine the following problem setup:

Now, one could solve this problem using relativity and rotational motion in three-dimensional space, or one could instead enlist pseudoforces to vastly simplify the problem, allowing us to deal with it using only 2D kinematics. Which sounds easier to you?

## @garyp 2014-04-18 14:04:07

The force you feel when you round a corner in your car is the friction force of the car seat on your behind, and perhaps the pushing force of the door on your shoulder. These are

very realforces that occur when your car tries to turn while your body tries to continue moving in a straight line.But from your point of view in the car, with the windows painted black (!), you perceive yourself being thrust toward the door for no apparent reason. You feel as if there is a force acting on

you, and the friction on your pants and the compression of your shoulder are aresultof this force as you try to accelerate in the direction of that perceived force.Since your car windows are painted black, the only frame of reference you know about is the one attached to the car, so you (quickly, because you are about to crash) reformulate mechanics to account for your observations. You see yourself being accelerated toward the door, so you have no choice but to associate a force with that acceleration. You call it "centrifugal", and you write it all down ... quickly.

## @evil999man 2014-04-18 11:27:12

Suppose you are at a red light in your car. You apply Newton's second law on the street light. $$F=ma$$ $$F=0N, a=0ms^{-2}$$$$0N=0N$$

It works!!

Now the light turns green and you start accelerating. Suppose your acceleration is $1ms^{-2}$. According to you, you are at rest. Do you see your nose moving? Apparently not. It means your body is at rest wrt you. So street light has acceleration $-1ms^{-2}$ wrt you. Let's apply Newton's second law.

$$F=ma$$

Clearly, there is no force acting on it. And the light,say, has mass=$50kg$

$$0N=-50N$$

NOOOOOOOOOOOOO.....Your mind just blew, right? You see that you are unable to apply Newton's second law in an accelerating frame. Let's see how can we fix it.

IF we add $-50N$ on $LHS$ we will get the correct answer.

Hence, we define pseudo force as a

correction termwhich enables us to apply Newton's second law in accelerating frames. It has no real existence, it is just a mathematical force.Similarly, a centripetal force is needed to make you go in a circle. If you sit there, you have to apply a force outwards which we call centrifugal force, to use Newton's laws.

Centripetal force is a force which provides acceleration towards centre, say, Tension while moving the object round with string. So if, you apply $F=ma$ from the revolving object, you have to add centrifugal force as the object is at rest wrt itself.

You can explain what you experience while turning due to you inertia which resists you change in motion.

## @Patrick M 2014-04-18 16:35:58

I just... can't upvote a physics answer with a troll-dad avatar. (Just kidding, +1)

## @evil999man 2014-04-18 16:56:52

@PatrickM Nice

about mein your profile.## @AJMansfield 2014-04-24 01:32:26

Although I might mention, whenever you are using centrifugal force, and the radius is non-constant, you also need to add a corresponding Coriolis force to correct for a similar type of error.

## @1110101001 2015-06-21 01:38:49

So in a non-inertial radial reference frame, you have to add a fictitious centrifugal force to balance out the centripetal force so the object stays stationary form your radial viewpoint? However, if this is the case then (let's say you are on one of those circular spinny rides at an amusement park) these two forces should balance out so you should not feel any "push" against you from any side. Yet clearly, you do feel an outward push against you. What am I missing?

## @Steeven 2016-07-09 10:28:27

evil999man Very nice answer +1. @1110101001 the point is not if you feel the force or not. The point is if you accelerate. And from your own frame, you don't. Yes, you do feel the centrifugal force $F_{fug}$, but you are also holding on to the swing yourself causing a counter-force $F_{hold}$ to balance it. In total in your own frame: $$\sum F=F_{fug} - F_{hold} =0$$