#### [SOLVED] What is the difference between electric potential, potential difference (PD), voltage and electromotive force (EMF)?

By new her

This is a confused part ever since I started learning electricity. What is the difference between electric potential, potential difference (PD), voltage and electromotive force (EMF)? All of them have the same SI unit of Volt, right? I would appreciate an answer. The amount of work done by unit charge between any two nodes of current carrying circuit is called the potential difference between those nodes.

The amount of work done against the electric field by displacing (without acceleration) a unit test charge from one terminal to other terminal in an open circuit is called the electromotive force.

Obviously when we deal in static electricity the potential difference between two points in electric field is amount of work done against the electric field by displacing (without acceleration) a unit test charge from one point to another point, off course it doesn't depends on path because the electric field is conservative field.

Same is happen when current is flowing in a circuit, in this case the electric field is confined in physical boundaries of circuit components, but still it is conservative in nature. Hence the potential difference in a current carrying circuit will also the amount of work done by moving a unit test charge from one node to another node. In other scenario we can observe that the charge is already moving in the current carrying circuit, so amount of work done by these moving charges in the current carrying circuit is converted in heat, light, mechanical work etc.

In case of emf, when any circuit is open, the open terminals do have charge density difference, this difference in charge density create an electric field, the work done against this electric field in moving a unit test charge without acceleration from one terminal to another is called the electromotive force.. #### @user82578 2015-06-01 11:08:30

Potential differance is the electrical pressure between two points but voltage is the electrical pressure between any two live wires or one live wire and earth. #### @user1355 2011-10-06 16:04:22

Anyway the simple answer is e.m.f. is not a force in the mechanical sense. It measures the amount of work to be done for a unit charge to travel in a closed loop of a conducting material.

Let's make it more clear. In static case (ignoring time variation of any magnetic field), electric field at a point can be derived solely from a scalar as the negative of the gradient of this scalar. This scalar at any point is called the "electric potential" at that point. If two points are at different potentials then we say there exists a potential difference. Obviously it is the difference in the potentials that matters and not their absolute values. One can therefore arbitrarily assign a value zero for some fixed point who's potential may be considered constant and compare the potentials of other points with respect to it. In this way one need not have to always speak of potential difference but simply potentials.

Now, often this "electric potential" at some point in a conductor or a dielectric is called "voltage" at that point assigning the value of the voltage to be zero for earth since the potential of earth is constant for all practical purposes.

If there is no variation of magnetic field then the work done by an unit charge in a closed loop will be $0$. But if the magnetic field varies then it will be nonzero. Recall the formula: $$\nabla \times {E} = -\frac {\partial {B}}{\partial {t}}.$$

What it really implies is, it is impossible for an electric field, derived solely from a scalar potential, to maintain an electric current in a closed circuit. So an e.m.f. implies presence of some source other then a source which can only produce a scalar potential.

The following equation tells the whole story:

$$E = -\nabla \phi - \frac{\partial A}{\partial t},$$ where $\phi$ is the scalar potential and $A$ is the vector potential. #### @Ron Maimon 2011-10-06 16:53:38

People downvote sometimes not because you are wrong, but because you are repeating other people's answers without adding anything new. #### @ganzewoort 2011-10-06 17:01:50

sb1, your explanation again fails to explain the open-circuit emf. Even more interestingly, I'm curious to hear your explanation as to how the Faraday's law you're mentioning accounts for the voltage drop measured across a unipolar generator. This, perhaps, is for a separate question to be asked in stackexchange. #### @user1355 2011-10-06 17:52:42

@ganzewoort: "e.m.f. implies presence of some source other then a source which can only produce a scalar potential." That means the electric field is not conservative any more. That's all. In open circuit condition, a voltage will be generated between the ends which is not just the difference of scalar potential at the two ends. As for unipolar generator, yes, it will be a good idea to ask as a separate question. #### @ganzewoort 2011-10-06 18:43:02

I agree about the scalar potential (I think you've explained it very well and doesn't repeat what's been said so far). However, scalar potential is only a mathematical construct, created for convenience, which isn't inherent in the phenomena. I'm adding a separate question regarding the unipolar generator. #### @aleena 2015-01-18 12:20:43

To help you understand the difference, think of EMF as a measurement of Work being done and think of Electric Potential Energy as energy that has the "potential" to perform Work. As an analogy, EMF could be thought of (in the Mechanical realm) as one pushing a wheel barrel up a hill. (Or better yet, a car, with gasoline prices as they are today lol.). And think of Electric Potential Energy as the wheel barrel being at the top of the hill. If the wheel barrel was released, its' potential energy would be transformed into several different forms of energy in rolling down the hill (Frictional-Heat, Work done on air resistance; and if it collided with a wall at the bottom and came to rest, its' original Potential Energy would all have been transformed into different forms of energy upon coming to rest at the bottom. Now to get a bit more technical...

A. EMF (Electromotive Force)
work that has been done is by definition, the Work done within the EMF "seat" (the battery in this case) in raising the charges (Chemically) from the negative (-) terminal up to the positive (+) terminal thus maintain the ability to still provide the circuit with current.

B. ELECTRIC POTENTIAL ENERGY
As an analogy (I'll get a little funny on this one), imagine that a Woman and a Man see each other; say from six feet apart. They instantly have an attraction (overbearing) for one-another; enter into a trance and begin walking towards each other. The energy other folks would have to apply to hold both from continuing to walk towards each other, is analogically, the Electric Potential Energy. the folks would be holding the Man and Woman still while they retain their trance - maintain the force to come together. And in a direct definitional realm, it is the potential energy two separated oppositely charged (for positive potential) particles posses in the attraction to come together. As well, such can think of this from the perspective of the energy required to hold the two charges at rest (in a Static State) not allowing them to move towards one-another. Actually these are are same thing but usage is at different places.

Whenever we talk about batteries or a DC system, we use the Potential difference, as there is potential difference of 3.7 Volt.

The phrase "electro-motive force" (EMF) is used when a conductor cuts the flux inside the machine (Transformer, Generator, etc)

Voltage is used as Output from an electrical machine. #### @Ron Maimon 2011-10-05 22:23:47

EMF is used as a more general term to also include those situations where the integral of the electric field around a closed curve is not zero, so that the E field doesn't come from a pure potential. Usually, when people say potential, they mean that the potential is a function of the position, and when they say EMF, they mean it is a function of the loop.

You have nonintegrable E fields when you have changing magnetic fields, an inductance. Since the "voltage" is usually used for the pure electrical potential, people call the voltage produced by an inductance an "EMF". Outside the circuitry, the fields are negligible usually, and the EMF at any point is the electrostatic potential at that point. But inside the circuitry, in inductors, there's a difference. #### @hasnain 2012-01-04 16:04:03

potential difference and e.m.f has same unit because of voltage. firstly,potential difference is is define as the work done upon charge , while e.m.f(electro motive force) is the potential differnce maintain across the battery.we are normally cosidering the external cicuit there is also an inner circuit. V=IR
and E.M.F=Ir+IR sice E.M.F=I(r+R) therefore E.M.F=Ir+IR
AS WE KNOW V=IR
E.M.F=V+Ir #### @Martin Gales 2011-10-07 06:14:28

Voltage is a potential difference, due to the energy dissipation. Emf is a potential difference, due to the energy generation. #### @user1355 2011-10-07 07:27:09

"Voltage is a potential difference, due to the energy dissipation" are you sure? What about the voltage across an Inductor? #### @Martin Gales 2011-10-10 07:44:34

@sb1 Ok, for non-DC replace "dissipation" with "dissipation and consumption". #### @user1355 2011-10-11 15:41:14

Sorry still wrong. A.C. or D.C., energy is always conserved in a pure inductor and never "consumed" or "dissipated". If you apply a dc source across an inductor through a resistance then energy will be dissipated but again by the resister ($I^2r$ loss)and not by the inductor. In practice, an inductor will always have some resistance and a portion of energy will be dissipated and but again that's because of the resistance. #### @Martin Gales 2011-10-12 07:56:40

@sb1 At a time when the energy is converted into magnetic energy of the inductor, there is no difference, is the energy conserved or not. At this time the conductor draw energy from the circuit like a resistor. At a time when the inductor returns the stored energy into the circuit it works like a generator(a source of emf). #### @user1355 2011-10-12 08:54:01

No point in arguing :( You don't even know the meaning of consumption, dissipation, even energy conservation. #### @Martin Gales 2011-10-13 05:33:04

@sb1 Be please constructive. Words like "you are wrong", "you don't know" etc. show that you have a very little arguments. If you consume energy from the circuit, you can store it(inductor), dissipate it(resistor), whatever. In any case, you are a voltage source. This is a basic. #### @Siyuan Ren 2011-10-06 12:34:04

EDIT: Put simply, potential difference is the work done by electrostatic force on a unit charge, while EMF is the work done by anything other than electrostatic force on a unit charge.

I don't like the term "voltage". It seems to mean anything measured in volts. I'd rather say electric potential and electromotive force.

And the two are fundamentally different.

Electrostatic field is conservative, that is, over any loop $l$ we have $\oint_l \vec{E}\cdot\mathrm{d}\vec{l}=0$. In other words, the line integral of electrostatic field does not depend on the path, but only on end points. So we can define point by point a scalar value electrostatic potential $\varphi$, such that $$\varphi_A-\varphi_B=\int_A^B \vec{E}\cdot\mathrm{d}\vec{l},$$

or

$$q \left( \varphi_A-\varphi_B \right)=\int_A^B q\vec{E}\cdot\mathrm{d}\vec{l},$$

so $q\Delta\varphi$ equals the work done by electrostatic force.

In pratical application, electrons (and other carriers) flow in circuits. Since electrostatic field is conservative, it alone cannot move electrons in circles; it can only move them from lower potential to higher potential. You need another kind of force to move them from higher potential to lower ones in order to complete a cycle. This other force could be chemical, magnetic or even electric (vortex electric field, different from electrostatic field), and their equivalent contribution is called electromotive force. $$\mathrm{E.M.F.}=\int_\text{Circuit} \frac{\vec{F}}{q}\cdot\mathrm{d}\vec{l}$$ #### @ganzewoort 2011-10-06 14:16:37

your explanation (which repeats what I said regarding useful work) is confusing because it doesn't account for the difference in potentials when the circuit is not closed in a loop and which is called alternatively emf or voltage. #### @ganzewoort 2011-10-06 14:23:37

Also, observing electrons traveling spontaneously from lower potential to higher potential, as in your reply, is conterintuitive. Since it's a matter of conventions it would be preferable to choose a convention in a reverse sense. #### @Siyuan Ren 2011-10-06 14:52:33

@ganzewoort: Well, my explanation may be confusing, but potential and emf are fundamentally different. Even when the circuit is not closed, potential difference is not the same as emf. #### @ganzewoort 2011-10-06 15:01:07

first it should be understood that emf doesn't apply only for a closed loop, as you have inferred. As for whether or not it is a potential difference, it is, in the sense which I already explained. #### @Siyuan Ren 2011-10-06 15:13:40

@ganzewoort: I concede I was wrong about closed loop. But your explanation is not an explanation at all. You just describe how you measure the two, but does not address the conceptual difference. And your explanation is wrong. EMF cannot be directly measured. For example, the EMF of an inductor with non-zero resistance is different from the potential difference, and the only thing you can directly measure is that difference. #### @ganzewoort 2011-10-06 16:25:43

Yes, it can be measured directly. The emf of an unattached battery can be measured (in absence of current) with a high impedance electrometer, if you need accuracy. As for the conceptual difference, I already said that it emerges only in case you're interested in the maximum useful work which is given by the change in Gibbs free energy of, say, an electrochemical reaction. Otherwise all three terms express difference in potentials whereby potential by convention is such difference wrt a reference electrode while voltage, resp. emf, is potential difference between two arbitrary electrodes. #### @ganzewoort 2011-10-05 21:48:31

Potential, voltage and emf are practically the same thing. Potential is the value of volts of a given electrode you measure with respect to some standard electrode whose potential is considered zero (Normal Hydrogen Electrode (NHE), saturated calomel electrode (SCE) etc.) Voltage is the difference between two thus measured potentials of two electrodes. So, you see, potential is same as voltage but one of the electrodes is considered conditionally of potential zero. The term electromotive force you'd use in the stead of voltage if you intend to talk about the change of the Gibbs free energy which would amount to the useful work you can get from the given Galvanic element, say. In any event, that's just splitting hairs in my opinion, so you can use those terms interchangeably as long as it is clear what the reference electrode is. #### @Martin Beckett 2011-10-05 21:42:30

Electromotive force (Note; not a force) is simply the source of voltage in a circuit.