2011-01-17 20:53:29 8 Comments

I understand that you can (in principle) measure whether "free particles" (no forces) experience accelerations in order to tell whether a frame is inertial. But fundamentally, what determines which frames are inertial (i.e. what principle selects in which frames free particles will not appear to accelerate)? I've been told that the cosmic microwaves determine the ultimate rest frame of the universe, but that doesn't make sense to me, since one can still ask why that frame is an inertial frame.

Also, I understand that there are no real inertial frames in general relativity, but it seems like there certainly exists approximate inertial frames and we can ask why those frames are approximately inertial and not others. For example, in the frame of a person riding a merry go round, free particles appear to greatly accelerate; while in the frame of someone standing next to the merry go round there are no such great accelerations. Why does the guy (or gal) on the merry go round see free particles accelerating while the other guy doesn't.

And if you're gonna tell me that it's "the rest of the stuff in the universe" that determines whether the person on the merry go round sees free particles accelerate, I'll ask how you know that all that stuff is not spinning.

I hope this question sort of makes sense, it's been bothering me for a while and my study of relativity (most of special relativity and just the outline of general relativity) hasn't really clarified it for me much.

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## 7 comments

## @user12262 2013-07-10 23:38:26

More than the preceding answers I'd like to emphasize

We should, strictly speaking, differentiate between an inertial frame and an inertial coordinate system [...]", together withThe aspect in the characterization of an "inertial frame" which I'd like to consider first (for being exemplary) is expressed in the continuation of Rindler's statement: "

An inertial frame is simply an infinite set of point particles sitting still in space relative to each other."A corresponding operational requirement which may be considered as equivalent to what's meant by "

sitting still to each other", or at least necessary, would be that for any three distinct "point particle" members (${\textbf A}$, ${\textbf B}$ and ${\textbf Q}$) of the same inertial frame $S$(1)

participant ${\textbf A}$ finds for each of its signal indications ${\textbf A}_{\mathscr X}$ that

${\textbf A}$'s indication of having seen that ${\textbf Q}$ saw ${\textbf A}$'s indication of having seen ${\textbf B}$ saw ${\textbf A}$'s indication ${\textbf A}_{\mathscr X}$

is coincident to

${\textbf A}$'s indication of having seen that ${\textbf B}$ saw ${\textbf A}$'s indication of having seen ${\textbf Q}$ saw ${\textbf A}$'s indication ${\textbf A}_{\mathscr X}$.

Another important requirement characteristic of an "inertial frame" is that it should have members which are "

straight" to each other.A corresponding operational requirement (which may appear unexpectedly involved, but at least employs notions and operations just as they were used in (1) already) would be that for any two distinct "

point particle" members (${\textbf A}$ and ${\textbf B}$) of the same inertial frame $S$(2)

there exists (at least) one additional member ${\textbf J}$ of inertial frame $S$ such that

there exists one member ${\textbf K}$ of inertial frame $S$ (not necessarily distinct from ${\textbf J}$) whereby

participant ${\textbf A}$ finds for each of its signal indications ${\textbf A}_{\mathscr X}$ that

${\textbf A}$'s indication of having seen that ${\textbf J}$ saw ${\textbf A}$'s indication of having seen ${\textbf K}$ saw ${\textbf A}$'s indication ${\textbf A}_{\mathscr X}$

is coincident to

${\textbf A}$'s indication of having seen that ${\textbf B}$ saw ${\textbf A}$'s indication ${\textbf A}_{\mathscr X}$, and

participant ${\textbf B}$ finds for each of its signal indications ${\textbf B}_{\mathscr Y}$ that

${\textbf B}$'s indication of having seen that ${\textbf J}$ saw ${\textbf B}$'s indication of having seen ${\textbf K}$ saw ${\textbf B}$'s indication ${\textbf B}_{\mathscr Y}$

is coincident to

${\textbf B}$'s indication of having seen that ${\textbf A}$ saw ${\textbf B}$'s indication ${\textbf B}_{\mathscr Y}$.

Requirements (1) and (2) also have bearing on the characterization of members of the same inertial frame $S$ as "

not spinning around each other". Various ways of strengthening these requirements may of course be considered.The (seemingly) ultimate requirement arises from considering relations between different inertial frames: ($S$ and $F$): the requirements of characterization of one particular inertial frame ($S$, with members ${\textbf A}$, ${\textbf B}$ and others) should be strong/specific enough such that

(*) if some other participant, ${\textbf V}$, who is not a member of inertial frame $S$ (due to failing requirements such as (1) or (2) wrt. ${\textbf A}$, ${\textbf B}$ or other members of $S$) but who "met certain members of $S$ in passing"

is (nevertheless) identified as member of an inertial frame $F$ other than $S$ (due to ${\textbf V}$ satisfying all applicable requirements wrt. suitable participants other than ${\textbf A}$ or ${\textbf B}$ and so on)

then ${\textbf V}$ "moved uniformly" (straight and with "constant speed") among the members of $S$;

and all other members of inertial frame $F$ as well, with the same "speed" value as ${\textbf V}$.

(A relevant notion of "parallelism" or "the same direction of motion as ${\textbf V}$" only arises in the course of the stated requirement being satisfied.)

Of course, this refers to a notion of "speed" values for which an operational definition hasn't been stated here yet. It shouldn't be surprising, however, that the relational requirement (*) can not be satsfied if only sets of participants are being considered which are all "

straight" to each other in the sense of requirement (2). This necessitates the consideration of sets of participants whose geometric relations "extend in more than one dimension".A sufficient requirement (or rather, one more characterization of an "inertial frame" to which a corresponding operational definition can be constructed so that the relational requirement (*) finally can be satisfied) happens to be

(3)

that the members of the same inertial frame $S$ are "

flat" to each other. (Describing a corresponding operational definition is cumbersome.)Accordingly, it is not hard to construct examples of sets of events with "geometry" (causal relations) such that it would not contain any set of timelike worldlines (one for each participant) at all that would be strictly "

sitting still to each other" and "flat to each other"; but only to some approximation.## @Luboš Motl 2011-01-17 22:11:04

In special relativity, the inertial frames are just postulated to exist. There is nothing wrong whatsoever with such an approach: they're frames in which objects will move by constant velocities if no forces act upon them. Newton needed pretty much the same thing to define the laws of mechanics. The important point about relativity (both Galilean and Einsteinian) is that if one frame is inertial, other frames moving uniformly with respect to this inertial frame are inertial frames, too.

This is fully analogous to straight lines in the Euclidean geometry. (Inertial frames are just systems associated with observers whose world lines are straight lines in the spacetime - it's really the same thing in a different space.) Some lines on the paper simply are straight lines while others are not. One could also ask what is the principle that selects which lines are straight. Well, the principle is the set of axioms of the Euclidean geometry. One has to have a system that allows us to say things about the geometric objects - and being able to say whether a line is straight is among the "tools" we have to be given. If we describe the geometry in coordinates that we call Cartesian, then a straight line is given by $ax+by+c=0$.

There is no confusion here unless someone deliberately tries to produce it. Asking who dared to make some systems inertial and others not is analogous to asking why mathematics discriminates against some numbers - because some of them are primes while others are not. Well, mathematics discriminates and it has the full right to do so. It's the very purpose of mathematics - and science - to discriminate all the time. Every time we ask a question, we want to hear the right answer and discriminate against all the other possible answers - the wrong ones. The right answer inevitably discriminates - it treats various objects or numbers asymmetrically. No maths or science could work if someone required the permanent democracy between everyone.

In general relativity, the spacetime is curved and a curved spacetime contains no reference frames - or systems of coordinates - in which the space would look flat. It's simply not flat. So there are no exact inertial frames in general relativity. In general relativity, one may only approximate the notion of an inertial system. One possible definition is that an inertial frame is a good approximation for local phenomena around freely falling objects. If an elevator is freely falling, you may call the frame associated with this elevator "inertial".

However, here on the Earth, it is not the usual choice. We usually say that the freely falling elevator is accelerating i.e. non-inertial. On the contrary, it is the non-falling elevator at rest that is inertial - even though it is not associated with geodesics in general relativity. The choice of the falling elevator has the advantage that you don't have to include the gravitational force among the forces that act on the objects inside the elevator. The only thing you have to include is the crash that will kill you: it's not the free fall but the collision with the ground that becomes your fate. :-)

If you choose that the inertial system is linked to the elevator at rest, you have to add the attractive gravitational force to the equations for all objects on the Earth. Of course, that will make your description of high-velocity phenomena etc. a bit inaccurate. But it's simply the case that curved spacetimes - and nontrivial gravitational fields - can't be exactly described by special relativity (and its inertial frames) only. If this were possible, we wouldn't need general relativity. It's not possible and we need general relativity to describe gravity in the relativistic context.

In the broader cosmic context, away from the gravitational field of the Earth or the Sun, the approximate inertial frames can be defined by the freely moving objects. One of them will be the frame associated with the cosmic microwave background - the frame of spheres such that the total momentum hiding in the CMB photons that are crossing the sphere at each point of the sphere's surface is zero. The CMB frame determines not only what is the vanishing acceleration; it also determines what is the vanishing speed.

With this benchmark in place, one may discuss the motion of the Sun (and the Solar System), our Galaxy, galaxy clusters and superclusters where we belong etc. relatively to the CMB cosmic frame. Those speeds are kind of known. But it's useful to recall that these speeds don't really mean that the Solar System frame is far from inertial. It's because uniform speeds don't spoil the inertial character of the reference frame. So even though the Sun is moving relatively to the CMB frame, by a rather high speed, the system associated with the Sun - and properly oriented relatively to some other galaxies etc. - is inertial with a huge accuracy.

## @Joss L 2011-01-17 22:28:25

Thanks for your reply, Lubos. I may have more questions (or less questions) when I read through it again carefully, but I had a question about the analogy to Euclidean geometry (EG). In EG, as you say, the axioms determine which lines are straight, but in physics, it is experiments that determine which frames are inertial. I.e. I can accept that inertial frames are simply posited to be whatever they are in SR, but what principle picks out which frames those are in a real universe? Not sure if I'm making sense, I think I need to ponder all these answers for a while.

## @Luboš Motl 2011-01-17 22:41:44

Dear Joss, my goal was to make a much tighter analogy. Euclid's postulates en.wikipedia.org/wiki/Euclidean_geometry#Axioms contain the existence of a straight line connecting any pair of points, that's the number one. He doesn't really tell us "which" it is - we know it very well, anyway. In the same way, it's postulated in SR that any 2 events in spacetime may be connected by a straight world line. The observer on it will carry an inertial system.

## @Luboš Motl 2011-01-17 22:44:13

How would you answer "my" question "What principle picks out which lines on the paper in the real Universe are straight lines?" Just be prepared: whatever you will say, I will use as an answer to your question about the inertial frames because it's the same thing. ;-) In both cases, the Universe simply knows about the metric tensor (on paper or in spacetime) which says which lines are straight, which lines are curved, as well as distances, angles, and everything else in geometry. In SR, the metric tensor is non-dynamical and can be usefully fixed to (-1,1,1,1), in GR it is dynamical.

## @Joss L 2011-01-18 19:05:58

I think I get your point that straight lines in SR is exactly like geometry on a paper (although I don't quite understand why), but for some reason I still feel uneasy that the geometry is fixed in SR in one way but not another way. I.e. given three events do they lie on a straight line in SR or not? I understand that given a metric there is just one answer, but I don't understand why that metric is the way it is. (Not sure if I have a good enough understanding to talk about this intelligently yet, I seem to be confusing myself)

## @user7757 2013-03-27 03:27:38

A very entertaining and enlightening answer. Thanks!

## @user346 2011-01-18 02:17:05

The previous answers have covered every philosophical and epistemological aspect, of the question of inertial reference frames (IRFs), that I could think of. What has not been mentioned is a

physicalconstruction in terms of the kinematics of moving bodies. The reference for this answer is Michael Dickson's paper on "Quantum Reference Frames".This 106 year old construction is originally due to L. Lange ("

Ueber das Beharrungsgesetz", Leipziger Berichte 37: 333-351, 1885). Lange's defines an inertial frame of reference as (quoting from Dickson):Once we have this working definition of an IRF, we can easily start to see where it can fail and thus shed light on the inherent physical limitations of the concept. What triples of particles existing in Nature can actually satisfy this construction? Three hard spheres moving inertially in a box with elastic boundary conditions (3D billiards), three celestial bodies - stars or galaxies, three elementary particles - each case defining an IRF on mesoscopic, macroscopic and microscopic scales respectively.

It is clear that each such triple can serve as a basis for an IRF over some finite range of scales. So this discussion immediately suggests that in our non-scale-invariant Universe (i.e. with a hierarchy of scales - stars, billiards, atoms) there does not and cannot exist any single IRF valid on all scales.

For a more detailed discussion I strongly recommend reading Dickson's engrossing article.

## @Stan Liou 2011-01-18 00:29:29

In ordinary mechanics, inertial frames are defined by constant-velocity observers. This is still true in GTR--experimentally, "inertial motion" means "no proper acceleration", which can be measured by an accelerometer. The equivalence principle means that at least locally, mechanical systems act like there is no gravity, so on the conceptual level, GTR "inherits" inertial frames from ordinary mechanics, although in a more limited sense.

From the formal perspective, it's exactly as axiomatic as the Euclidean geometry you referenced above. Say you have two curves intersecting at p on a differentiable manifold, and in some coordinates they have same derivative at p, so you say that they're in the same direction. The equivalence classes define the

tangent spaceat p (which can also be done in a variety of other ways), which is a vector space of "directions from p". In particular, the velocity of a particle at some point is just the tangent vector of its curve in spacetime (wordline).So how do we interpret inertial motion as "having the same velocity"? To do so, we need to be able to compare two vectors between the tangent spaces of

different points. Or, equivalent, to be able to transport vectors (and in general, tensors) from one point or another. The mathematical device that lets us do this is called theconnection, and like many things in mathematics, it is completely general, with infinitely many possible distict connections on the same manifold. "Inertial motion" or "geodesic" will then just be a curve whose tangent vector stays the same when transported between infinitesimally close points.Here's where the GTR's postulate comes in. Assume that it is "metric-compatible", which means that the inner product between two vectors likewise unchanged when transported along a curve. Also assume that the connection is "torsion-free", which is a fancy way of saying that if you transport a vector around a small loop in spacetime back to the starting point, then to first order it is unchanged. It turns out that these conditions uniquely determine the connection. (Incidentally, in the second-order change in the loop transport operation defines the Riemann curvature.)

In other words, GTR postulates that the "constant velocity" curves are exactly the length-extremizing curves dictated by the metric tensor $g_{\mu\nu}$. And just like Euclidean postulates, it is quite possible to take a contradictory option. For example, Einstein-Cartan theory of gravity does not have the above assumptions, and in its torsion terms allows spin angular momentum and its

gravitationalexchange with orbital angular momentum, unlike in GTR.## @Ted Bunn 2011-01-17 21:19:14

As you say, there's a perfectly sensible operational definition of an inertial frame: it's one in which free particles move with constant velocity. Even in general relativity, it makes sense to talk about inertial frames, but only locally. To be precise, an inertial frame is well-defined only in an infinitesimal neighborhood of a spacetime point, although in practice it's a sensible approximation to extend such a frame to a finite neighborhood, as long as the size is small compared to any length scales associated with spacetime curvature.

The fact that there are inertial frames is essentially an axiom of general relativity. The theory is based on the idea that spacetime has a certain geometric structure, which allows for the existence of geodesics, along which free particles travel. Within a sufficiently small neighborhood the geodesics near a given point "look" to a good approximation like what you'd get in an inertial frame.

So there's not really a good answer to the question of why inertial frames exist: it's just part of the assumed framework of the theory. But that's not quite what you asked. You asked if there's a reason why a given frame S is inertial and a different frame S' isn't. It sort of depends on what you think would count as a reason. For a given spacetime geometry, the geodesics are well-specified (as solutions to a certain differential equation, or as curves that have certain geometrical properties). The inertial frames are the frames that make the geodesics look like straight lines. It's all terribly mathematically well-defined and self-consistent, but it may not have the intuitive feel of a "reason why."

You mention the possibility that the reason is "all the other stuff in the universe." As you may know, this idea has a noble pedigree: it goes by the name of Mach's principle. Einstein was apparently quite enamored of Mach's principle when he was coming up with general relativity, and he would probably have been very happy if the theory had the property that the inertial frames were determined by all the other matter in the Universe. But general relativity's relationship with Mach's principle is complicated and problematic, to say the least. For instance, good old flat Minkowski spacetime is a perfectly valid solution to the equations of general relativity. That solution has well-defined inertial frames, even though there is no matter around to "cause" them.

## @Joss L 2011-01-17 21:53:45

You've given me a lot to think about. I have encountered Mach's principle when searching for this topic on the internet, but I haven't been able to find a good explanation on how such ideas are understood by modern physics yet (if anyone knows of a good source, I'd love to read it). It sounds like I'll need a good understanding of general relativity before I can really understand this issue, but that will probably take me a couple more years.

## @Philip Gibbs - inactive 2011-01-17 21:16:56

In general relativity it is the gravitational field that determines which local frame of reference are local inertial frames. I talk about "local" frames because as you observed in your question, there are no global inertial reference frames in curved spacetime.

The gravitational field is represented by a metric tensor field. Given such a metric you can plot the timelike geodesics through any event. These are the trajectories that locally maximise the integrated proper-time calculated using the metric. Anything that moves along such a geodesic is in a local inertial frame.

The cosmic microwave background does not define a preferred frame from the point of view of the equations of motion. It is just one of many reference frames that you can find in the universe by observation. In fact there are many different frames of reference that you could define based on just the cosmic background radiation, and they only coincide in a perfectly homogeneous universe, but the universe is not locally homogeneous. Furthermore these reference frames are in general mostly not inertial frames.

## @Noldorin 2011-01-17 21:23:58

Good answer. Indeed, local inertial frames are the only ones that exist, and in general inertial frames cannot be properly defined without reference to GR>

## @Joss L 2011-01-17 21:44:49

Thanks Philip. So If I understand you correctly, there is a field (similar to the electric field?) in spacetime (the metric tensor), and that determines which frames are approximately inertial. So I guess then to understand the correct answer to my question, I would need to understand why that field is the way that it is. From what I gather, this is explained in general relativity, but does this mean there is no way to answer the question in special relativity? I.e. suppose we had a universe where special relativity held but not GR, how would we decide which frames are inertial?

## @Philip Gibbs - inactive 2011-01-18 07:32:11

Yes the metric is a field like the electric field in the sense that it is described by a set of real numbers for each point in spacetime. Actually the electric and magnetic field are more closely allied to the curvature metric that is another field that can be derived from the metrix, just as the electro-magnetic field can be derived from a vector potential. The evolution of the metric is described by the einstein field equations.

## @Philip Gibbs - inactive 2011-01-18 07:37:36

In special relativity there is still a metric but it is fixed and constant (in rectilinear co-ordinates). The inertial frames can be derived from the metric (the Minkowski metric) by plotting the geodesics in the same way, but the result is simpler and global inertial frames exist in this special case.

## @Joss L 2011-01-18 18:59:06

Oh, I didn't understand that there's a metric in special relativity as well. In that case, I'm still not quite sure how inertial frames are picked. I get that they are the straight lines according to the metric, but couldn't there be a different metric which calls different lines straight? (I'm not sure that question makes sense, so feel free to say so if that is the case. I'm really starting to think I need to learn the math of GR to understand any of this. It seems from people's responses that talking about moving spaceships and Lorentz transformations just won't cut it)

## @Philip Gibbs - inactive 2011-01-20 13:18:13

There is only one metric. Having more than one metric would mean having more than one gravitational field. It does not make sense.

## @Philip Gibbs - inactive 2011-01-20 13:19:55

The metric in special relativity is just the expression that tells you the spacetime distance between points.

## @Andrew Spott 2011-01-17 21:10:54

Well, from the point of view of an inertial reference frame, angular momentum and linear momentum are conserved, and when you aren't in an inertial reference frame, they aren't conserved.

As an example, consider that you are on a spaceship accelerating away from a lone sun. (ignoring an expanding universe for the moment). In your frame, the sun is accelerating away from you, without anything to cause such an acceleration. Momentum is not conserved from your frame of reference, and thus, you aren't in an inertial reference frame.

Hopefully this helps.

## @Joss L 2011-01-17 21:28:58

Thanks. So it seems from your answer that the thing that is different between the "spaceship accelerating away from the stationary sun" frame and the "sun accelerating away from the stationary spaceship" frame is that in the former frame there is an explanation for the acceleration (rocket exhaust), but there is no explanation for the accelerating sun in the latter frame. I guess that makes sense, but what principle decides that the sun is in an inertial frame? I.e. why doesn't someone in that frame see free particles accelerate (in a manner unrelated to the spaceship)?

## @Paul B 2017-03-27 18:18:47

Not only is there no explanation for the acceleration of the sun, the acceleration of the sun would have to somehow be proportional to the mass of the rocket and the exhaust with no justification. Or, the only justification is to say it is the reciprocal of what you get when you invoke the laws of physics from the perspective of the sun. That makes the sun-frame special (inertial).