By Groctel

2019-01-07 17:13:42 8 Comments

I'm doing some physics homework calculating the total resistance between points A and B and while some circuits are comprehensible, there are two that I can't understand how they work at all.

So, it is my pleasure to present to you these two monstrosities:

The divided square The hellborn triangles of death

How do I approach the crossing resistances in each one? Here's where I am as of writing this post:

The divided square:

  • The two 10k resistances are parallel to each other
  • The 20k and 9k resistances are parallel to each other
  • I don't know what to do with the 5k one

The hellborn triangles of death:

  • The first and last pair of 5k resistances are parallel to each other
  • The bottom center 5k resistance is in series with the previous two couples
  • I don't know what to do with the 15k ones

So, long story short, how should I handle these situations when the resistances are connected by both sides and the circuit looks like the voltage should converge inside them and start burning?


@AdvancedNewbie 2019-01-07 23:40:37

I would apply an abritrary voltage and calculate current in each loop using mesh currents. Then R = Vab/I_total. Then the circuit can be as messy as it wants, but it won't really matter. You'll always be able to solve the matrix for unknowns.

@user212727 2019-01-07 20:33:38

The second circuit can be solved easily by perpendicular axis of symmetry.enter image description here

@Acccumulation 2019-01-07 18:18:28

For the top one, you can separate out the $9 k\Omega$ resistor at the top, since it's in series with the rest. Now you have a graph with four nodes and five edges. You can assign the variables $V_1$ through $V_4$ to the nodes, but WLOG you can consider the top node to be 0 and the bottom to be 1, so that leaves just the left and right voltages. You then have currents $I_1$ through $I_5$ through the edges. You can then start applying the circuit laws to these variables: for each edge, the current is equal to change in voltage divided by the resistance. The net current through each edge is zero (if you take current flowing in to be positive and current flowing out to be negative, that is). You'll then get a bunch of equations, and solving them will give the effective resistances.

It's probably best to work out what the effective resistances are from basic principles and algebra first, and then try to work through applying Y-Δ to get a sense of how that works.

Also, any symmetry in the diagram should be preserved in the values. The second circuit has left-right symmetries, so the currents should be symmetrical: the two top resistors should have the same currents as each other, the two outsides diagonal resistors should have the same as each other, and the two inside diagonal should have the same as each other. So you can use just four variables to represent the nine different currents.

@Pietro Oliva 2019-01-07 17:25:32

Try then to apply the Y-$\Delta$ tranformations! I am glad you found the light! If you cannot carry calculation drop again here a line and i'll try to work more on the answer!

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