On SQL Server 2008 and higher, you should CONVERT to date:

SELECT CONVERT(date, getdate())

On older versions, you can do the following:

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @your_date))

for example

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))

gives me

2008-09-22 00:00:00.000

Pros:

• No varchar<->datetime conversions required
• No need to think about locale

My common approach to get date without the time part..

 SELECT CONVERT(VARCHAR(MAX),GETDATE(),103)

 SELECT CAST(GETDATE() AS DATE)

Simply you can do this way:

SELECT CONVERT(date, getdate())
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @your_date))
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))

Outputs as:

2008-09-22 00:00:00.000

Or simply do like this:

SELECT CONVERT (DATE, GETDATE()) 'Date Part Only'

Result:

Date Part Only
--------------
2013-07-14

On SQL Server 2000

CAST(
(
    STR( YEAR( GETDATE() ) ) + '/' +
    STR( MONTH( GETDATE() ) ) + '/' +
    STR( DAY( GETDATE() ) )
)
AS DATETIME)

select Cast (getdate() as Date) yourDate

If you are assigning the results to a column or variable, give it the DATE type, and the conversion is implicit.

DECLARE @Date DATE = GETDATE()   

SELECT @Date   --> 2017-05-03

SELECT CONVERT(VARCHAR,DATEADD(DAY,-1,GETDATE()),103) --21/09/2011

SELECT CONVERT(VARCHAR,DATEADD(DAY,-1,GETDATE()),101) --09/21/2011

SELECT CONVERT(VARCHAR,DATEADD(DAY,-1,GETDATE()),111) --2011/09/21

SELECT CONVERT(VARCHAR,DATEADD(DAY,-1,GETDATE()),107) --Sep 21, 2011

If you are using SQL Server 2012 or above versions,

Use Format() function.

There are already multiple answers and formatting types for SQL server. But most of the methods are somewhat ambiguous and it would be difficult for you to remember the numbers for format type or functions with respect to Specific Date Format. That's why in next versions of SQL server there is better option.

FORMAT ( value, format [, culture ] )

Culture option is very useful, as you can specify date as per your viewers.

You have to remember d (for small patterns) and D (for long patterns).

1."d" - Short date pattern.

2009-06-15T13:45:30 -> 6/15/2009 (en-US)
2009-06-15T13:45:30 -> 15/06/2009 (fr-FR)
2009-06-15T13:45:30 -> 2009/06/15 (ja-JP)

2."D" - Long date pattern.

2009-06-15T13:45:30 -> Monday, June 15, 2009 (en-US)
2009-06-15T13:45:30 -> 15 июня 2009 г. (ru-RU)
2009-06-15T13:45:30 -> Montag, 15. Juni 2009 (de-DE)

More examples in query.

DECLARE @d DATETIME = '10/01/2011';
SELECT FORMAT ( @d, 'd', 'en-US' ) AS 'US English Result'
      ,FORMAT ( @d, 'd', 'en-gb' ) AS 'Great Britain English Result'
      ,FORMAT ( @d, 'd', 'de-de' ) AS 'German Result'
      ,FORMAT ( @d, 'd', 'zh-cn' ) AS 'Simplified Chinese (PRC) Result'; 

SELECT FORMAT ( @d, 'D', 'en-US' ) AS 'US English Result'
      ,FORMAT ( @d, 'D', 'en-gb' ) AS 'Great Britain English Result'
      ,FORMAT ( @d, 'D', 'de-de' ) AS 'German Result'
      ,FORMAT ( @d, 'D', 'zh-cn' ) AS 'Chinese (Simplified PRC) Result';

US English Result Great Britain English Result  German Result Simplified Chinese (PRC) Result
----------------  ----------------------------- ------------- -------------------------------------
10/1/2011         01/10/2011                    01.10.2011    2011/10/1

US English Result            Great Britain English Result  German Result                    Chinese (Simplified PRC) Result
---------------------------- ----------------------------- -----------------------------  ---------------------------------------
Saturday, October 01, 2011   01 October 2011               Samstag, 1. Oktober 2011        2011年10月1日

If you want more formats, you can go to:

1. Standard Date and Time Format Strings
2. Custom Date and Time Format Strings

Starting from SQL SERVER 2012, you can do this:

SELECT FORMAT(GETDATE(), 'yyyy-MM-dd 00:00:00.000')

Date:

SELECT CONVERT(date, GETDATE())
SELECT CAST(GETDATE() as date)

Time:

SELECT CONVERT(time , GETDATE() , 114)
SELECT CAST(GETDATE() as time)

SELECT CONVERT(date, getdate())

SQLServer 2008 now has a 'date' data type which contains only a date with no time component. Anyone using SQLServer 2008 and beyond can do the following:

SELECT CONVERT(date, GETDATE())

Okay, Though I'm bit late :), Here is the another solution.

SELECT CAST(FLOOR(CAST(GETDATE() AS FLOAT)) as DATETIME)

Result

2008-09-22 00:00:00.000

And if you are using SQL Server 2012 and higher then you can use FORMAT() function like this -

SELECT FORMAT(GETDATE(), 'yyyy-MM-dd')

You can simply use the code below to get only the date part and avoid the time part in SQL:

SELECT SYSDATE TODAY FROM DUAL; 

DECLARE @yourdate DATETIME = '11/1/2014 12:25pm'    
SELECT CONVERT(DATE, @yourdate)

If using SQL 2008 and above:

select cast(getdate() as date)

If you need result in varchar datatype you should go through

SELECT CONVERT(DATE, GETDATE()) --2014-03-26
SELECT CONVERT(VARCHAR(10), GETDATE(), 111) --2014/03/26

which is already mentioned above

If you need result in date and time format you should go through any of the below query

1) SELECT CONVERT(DATETIME,CONVERT(VARCHAR(10), GETDATE(), 111)) as OnlyDate --2014-03-26 00:00:00.000

2) SELECT CONVERT(DATETIME,CONVERT(VARCHAR(10), GETDATE(), 112)) as OnlyDate --2014-03-26 00:00:00.000

3)

 DECLARE  @OnlyDate DATETIME
   SET @OnlyDate = DATEDIFF(DD, 0, GETDATE())
   SELECT @OnlyDate AS OnlyDate

--2014-03-26 00:00:00.000

To obtain the result indicated, I use the following command.

SELECT CONVERT(DATETIME,CONVERT(DATE,GETDATE()))

I holpe it is useful.

This was missing in all answers, may not be the most efficient but very easy to write and understand, no style needed, no complex date functions.

SELECT CONVERT(DATETIME,CONVERT(DATE,((GETDATE()))))

SELECT * FROM tablename WHERE CAST ([my_date_time_var] AS DATE)= '8/5/2015'

I favor the following which wasn't mentioned:

DATEFROMPARTS(DATEPART(yyyy, @mydatetime), DATEPART(mm, @mydatetime), DATEPART(dd, @mydatetime))

It also doesn't care about local or do a double convert -- although each 'datepart' probably does math. So it may be a little slower than the datediff method, but to me it is much more clear. Especially when I want to group by just the year and month (set the day to 1).

SELECT DATEADD(DD, DATEDIFF(DD, 0, GETDATE()), 0)

SELECT DATEADD(DAY, 0, DATEDIFF(DAY,0, GETDATE()))

SELECT CONVERT(DATETIME, CONVERT(VARCHAR(10), GETDATE(), 101))

Edit: The first two methods are essentially the same, and out perform the convert to varchar method.

I know this is old, but I do not see where anyone stated it this way. From what I can tell, this is ANSI standard.

SELECT CAST(CURRENT_TIMESTAMP AS DATE)

It would be good if Microsoft could also support the ANSI standard CURRENT_DATE variable.

Date(date&time field) and DATE_FORMAT(date&time,'%Y-%m-%d') both returns only date from date&time

 Convert(nvarchar(10), getdate(), 101) --->  5/12/14

 Convert(nvarchar(12), getdate(), 101) --->  5/12/2014

You can use the CONVERT function to return only the date. See the link(s) below:

Date and Time Manipulation in SQL Server 2000

CAST and CONVERT

The syntax for using the convert function is:

CONVERT ( data_type [ ( length ) ] , expression [ , style ] ) 

Even using the ancient MSSQL Server 7.0, the code here (courtesy of this link) allowed me to get whatever date format I was looking for at the time:

PRINT '1) Date/time in format MON DD YYYY HH:MI AM (OR PM): ' + CONVERT(CHAR(19),GETDATE())  
PRINT '2) Date/time in format MM-DD-YY: ' + CONVERT(CHAR(8),GETDATE(),10)  
PRINT '3) Date/time in format MM-DD-YYYY: ' + CONVERT(CHAR(10),GETDATE(),110) 
PRINT '4) Date/time in format DD MON YYYY: ' + CONVERT(CHAR(11),GETDATE(),106)
PRINT '5) Date/time in format DD MON YY: ' + CONVERT(CHAR(9),GETDATE(),6) 
PRINT '6) Date/time in format DD MON YYYY HH:MM:SS:MMM(24H): ' + CONVERT(CHAR(24),GETDATE(),113)

It produced this output:

1) Date/time in format MON DD YYYY HH:MI AM (OR PM): Feb 27 2015  1:14PM
2) Date/time in format MM-DD-YY: 02-27-15
3) Date/time in format MM-DD-YYYY: 02-27-2015
4) Date/time in format DD MON YYYY: 27 Feb 2015
5) Date/time in format DD MON YY: 27 Feb 15
6) Date/time in format DD MON YYYY HH:MM:SS:MMM(24H): 27 Feb 2015 13:14:46:630

For return in date format

CAST(OrderDate AS date)

The above code will work in sql server 2010

It will return like 12/12/2013

For SQL Server 2012 use the below code

CONVERT(VARCHAR(10), OrderDate , 111)

why don't you use DATE_FORMAT( your_datetiem_column, '%d-%m-%Y' ) ?

EX: select DATE_FORMAT( some_datetime_column, '%d-%m-%Y' ) from table_name

you can change sequence of m,d and year by re-arranging '%d-%m-%Y' part

You can use following for date part and formatting the date:

DATENAME => Returns a character string that represents the specified datepart of the specified date

DATEADD => The DATEPART() function is used to return a single part of a date/time, such as year, month, day, hour, minute, etc.

DATEPART =>Returns an integer that represents the specified datepart of the specified date.

CONVERT() = > The CONVERT() function is a general function that converts an expression of one data type to another. The CONVERT() function can be used to display date/time data in different formats.