By Devdatta Tengshe


2008-08-14 16:41:25 8 Comments

I work in VBA, and want to parse a string eg

<PointN xsi:type='typens:PointN' 
xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' 
xmlns:xs='http://www.w3.org/2001/XMLSchema'>
    <X>24.365</X>
    <Y>78.63</Y>
</PointN>

and get the X & Y values into two separate integer variables.

I'm a newbie when it comes to XML, since I'm stuck in VB6 and VBA, because of the field I work in.

How do I do this?

8 comments

@rjzii 2008-08-14 16:47:07

This is a bit of a complicated question, but it seems like the most direct route would be to load the XML document or XML string via MSXML2.DOMDocument which will then allow you to access the XML nodes.

You can find more on MSXML2.DOMDocument at the following sites:

@TJ Wilkinson 2016-11-30 22:13:25

Often it is easier to parse without VBA, when you don't want to enable macros. This can be done with the replace function. Enter your start and end nodes into cells B1 and C1.

Cell A1: {your XML here}
Cell B1: <X>
Cell C1: </X>
Cell D1: =REPLACE(A1,1,FIND(A2,A1)+LEN(A2)-1,"")
Cell E1: =REPLACE(A4,FIND(A3,A4),LEN(A4)-FIND(A3,A4)+1,"")

And the result line E1 will have your parsed value:

Cell A1: {your XML here}
Cell B1: <X>
Cell C1: </X>
Cell D1: 24.365<X><Y>78.68</Y></PointN>
Cell E1: 24.365

@No Name 2015-10-13 13:29:42

Add reference Project->References Microsoft XML, 6.0 and you can use example code:

    Dim xml As String

    xml = "<root><person><name>Me </name> </person> <person> <name>No Name </name></person></root> "
    Dim oXml As MSXML2.DOMDocument60
    Set oXml = New MSXML2.DOMDocument60
    oXml.loadXML xml
    Dim oSeqNodes, oSeqNode As IXMLDOMNode

    Set oSeqNodes = oXml.selectNodes("//root/person")
    If oSeqNodes.length = 0 Then
       'show some message
    Else
        For Each oSeqNode In oSeqNodes
             Debug.Print oSeqNode.selectSingleNode("name").Text
        Next
    End If 

be careful with xml node //Root/Person is not same with //root/person, also selectSingleNode("Name").text is not same with selectSingleNode("name").text

@Maury Markowitz 2018-03-29 19:04:23

Some questions: why is the path //root, and not /root? And if I have a single person in my oSeqNode, how do I subselect all the <telephone>'s within just that person?

@Tommie C. 2011-04-21 16:30:39

Update

The procedure presented below gives an example of parsing XML with VBA using the XML DOM objects. Code is based on a beginners guide of the XML DOM.

Public Sub LoadDocument()
Dim xDoc As MSXML.DOMDocument
Set xDoc = New MSXML.DOMDocument
xDoc.validateOnParse = False
If xDoc.Load("C:\My Documents\sample.xml") Then
   ' The document loaded successfully.
   ' Now do something intersting.
   DisplayNode xDoc.childNodes, 0
Else
   ' The document failed to load.
   ' See the previous listing for error information.
End If
End Sub

Public Sub DisplayNode(ByRef Nodes As MSXML.IXMLDOMNodeList, _
   ByVal Indent As Integer)

   Dim xNode As MSXML.IXMLDOMNode
   Indent = Indent + 2

   For Each xNode In Nodes
      If xNode.nodeType = NODE_TEXT Then
         Debug.Print Space$(Indent) & xNode.parentNode.nodeName & _
            ":" & xNode.nodeValue
      End If

      If xNode.hasChildNodes Then
         DisplayNode xNode.childNodes, Indent
      End If
   Next xNode
End Sub

Nota Bene - This initial answer shows the simplest possible thing I could imagine (at the time I was working on a very specific issue) . Naturally using the XML facilities built into the VBA XML Dom would be much better. See the updates above.

Original Response

I know this is a very old post but I wanted to share my simple solution to this complicated question. Primarily I've used basic string functions to access the xml data.

This assumes you have some xml data (in the temp variable) that has been returned within a VBA function. Interestingly enough one can also see how I am linking to an xml web service to retrieve the value. The function shown in the image also takes a lookup value because this Excel VBA function can be accessed from within a cell using = FunctionName(value1, value2) to return values via the web service into a spreadsheet.

sample function


openTag = "<" & tagValue & ">"
closeTag = "< /" & tagValue & ">" 

' Locate the position of the enclosing tags startPos = InStr(1, temp, openTag) endPos = InStr(1, temp, closeTag) startTagPos = InStr(startPos, temp, ">") + 1 ' Parse xml for returned value Data = Mid(temp, startTagPos, endPos - startTagPos)

@mvanle 2014-12-30 11:24:13

You can use a XPath Query:

Dim objDom As Object        '// DOMDocument
Dim xmlStr As String, _
    xPath As String

xmlStr = _
    "<PointN xsi:type='typens:PointN' " & _
    "xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' " & _
    "xmlns:xs='http://www.w3.org/2001/XMLSchema'> " & _
    "    <X>24.365</X> " & _
    "    <Y>78.63</Y> " & _
    "</PointN>"

Set objDom = CreateObject("Msxml2.DOMDocument.3.0")     '// Using MSXML 3.0

'/* Load XML */
objDom.LoadXML xmlStr

'/*
' * XPath Query
' */        

'/* Get X */
xPath = "/PointN/X"
Debug.Print objDom.SelectSingleNode(xPath).text

'/* Get Y */
xPath = "/PointN/Y"
Debug.Print objDom.SelectSingleNode(xPath).text

@Bob Wheatley 2015-01-12 18:30:13

Here is a short sub to parse a MicroStation Triforma XML file that contains data for structural steel shapes.

'location of triforma structural files
'c:\programdata\bentley\workspace\triforma\tf_imperial\data\us.xml

Sub ReadTriformaImperialData()
Dim txtFileName As String
Dim txtFileLine As String
Dim txtFileNumber As Long

Dim Shape As String
Shape = "w12x40"

txtFileNumber = FreeFile
txtFileName = "c:\programdata\bentley\workspace\triforma\tf_imperial\data\us.xml"

Open txtFileName For Input As #txtFileNumber

Do While Not EOF(txtFileNumber)
Line Input #txtFileNumber, txtFileLine
    If InStr(1, UCase(txtFileLine), UCase(Shape)) Then
        P1 = InStr(1, UCase(txtFileLine), "D=")
        D = Val(Mid(txtFileLine, P1 + 3))

        P2 = InStr(1, UCase(txtFileLine), "TW=")
        TW = Val(Mid(txtFileLine, P2 + 4))

        P3 = InStr(1, UCase(txtFileLine), "WIDTH=")
        W = Val(Mid(txtFileLine, P3 + 7))

        P4 = InStr(1, UCase(txtFileLine), "TF=")
        TF = Val(Mid(txtFileLine, P4 + 4))

        Close txtFileNumber
        Exit Do
    End If
Loop
End Sub

From here you can use the values to draw the shape in MicroStation 2d or do it in 3d and extrude it to a solid.

@DK. 2010-05-09 02:19:29

This is an example OPML parser working with FeedDemon opml files:

Sub debugPrintOPML()

' http://msdn.microsoft.com/en-us/library/ms763720(v=VS.85).aspx
' http://msdn.microsoft.com/en-us/library/system.xml.xmlnode.selectnodes.aspx
' http://msdn.microsoft.com/en-us/library/ms256086(v=VS.85).aspx ' expressions
' References: Microsoft XML

Dim xmldoc As New DOMDocument60
Dim oNodeList As IXMLDOMSelection
Dim oNodeList2 As IXMLDOMSelection
Dim curNode As IXMLDOMNode
Dim n As Long, n2 As Long, x As Long

Dim strXPathQuery As String
Dim attrLength As Byte
Dim FilePath As String

FilePath = "rss.opml"

xmldoc.Load CurrentProject.Path & "\" & FilePath

strXPathQuery = "opml/body/outline"
Set oNodeList = xmldoc.selectNodes(strXPathQuery)

For n = 0 To (oNodeList.length - 1)
    Set curNode = oNodeList.Item(n)
    attrLength = curNode.Attributes.length
    If attrLength > 1 Then ' or 2 or 3
        Call processNode(curNode)
    Else
        Call processNode(curNode)
        strXPathQuery = "opml/body/outline[position() = " & n + 1 & "]/outline"
        Set oNodeList2 = xmldoc.selectNodes(strXPathQuery)
        For n2 = 0 To (oNodeList2.length - 1)
            Set curNode = oNodeList2.Item(n2)
            Call processNode(curNode)
        Next
    End If
        Debug.Print "----------------------"
Next

Set xmldoc = Nothing

End Sub

Sub processNode(curNode As IXMLDOMNode)

Dim sAttrName As String
Dim sAttrValue As String
Dim attrLength As Byte
Dim x As Long

attrLength = curNode.Attributes.length

For x = 0 To (attrLength - 1)
    sAttrName = curNode.Attributes.Item(x).nodeName
    sAttrValue = curNode.Attributes.Item(x).nodeValue
    Debug.Print sAttrName & " = " & sAttrValue
Next
    Debug.Print "-----------"

End Sub

This one takes multilevel trees of folders (Awasu, NewzCrawler):

...
Call xmldocOpen4
Call debugPrintOPML4(Null)
...

Dim sText4 As String

Sub debugPrintOPML4(strXPathQuery As Variant)

Dim xmldoc4 As New DOMDocument60
'Dim xmldoc4 As New MSXML2.DOMDocument60 ' ?
Dim oNodeList As IXMLDOMSelection
Dim curNode As IXMLDOMNode
Dim n4 As Long

If IsNull(strXPathQuery) Then strXPathQuery = "opml/body/outline"

' http://msdn.microsoft.com/en-us/library/ms754585(v=VS.85).aspx
xmldoc4.async = False
xmldoc4.loadXML sText4
If (xmldoc4.parseError.errorCode <> 0) Then
   Dim myErr
   Set myErr = xmldoc4.parseError
   MsgBox ("You have error " & myErr.reason)
Else
'   MsgBox xmldoc4.xml
End If

Set oNodeList = xmldoc4.selectNodes(strXPathQuery)

For n4 = 0 To (oNodeList.length - 1)
    Set curNode = oNodeList.Item(n4)
    Call processNode4(strXPathQuery, curNode, n4)
Next

Set xmldoc4 = Nothing

End Sub

Sub processNode4(strXPathQuery As Variant, curNode As IXMLDOMNode, n4 As Long)

Dim sAttrName As String
Dim sAttrValue As String
Dim x As Long

For x = 0 To (curNode.Attributes.length - 1)
    sAttrName = curNode.Attributes.Item(x).nodeName
    sAttrValue = curNode.Attributes.Item(x).nodeValue
    'If sAttrName = "text"
    Debug.Print strXPathQuery & " :: " & sAttrName & " = " & sAttrValue
    'End If
Next
    Debug.Print ""

If curNode.childNodes.length > 0 Then
    Call debugPrintOPML4(strXPathQuery & "[position() = " & n4 + 1 & "]/" & curNode.nodeName)
End If

End Sub

Sub xmldocOpen4()

Dim oFSO As New FileSystemObject ' Microsoft Scripting Runtime Reference
Dim oFS
Dim FilePath As String

FilePath = "rss_awasu.opml"
Set oFS = oFSO.OpenTextFile(CurrentProject.Path & "\" & FilePath)
sText4 = oFS.ReadAll
oFS.Close

End Sub

or better:

Sub xmldocOpen4()

Dim FilePath As String

FilePath = "rss.opml"

' function ConvertUTF8File(sUTF8File):
' http://www.vbmonster.com/Uwe/Forum.aspx/vb/24947/How-to-read-UTF-8-chars-using-VBA
' loading and conversion from Utf-8 to UTF
sText8 = ConvertUTF8File(CurrentProject.Path & "\" & FilePath)

End Sub

but I don't understand, why xmldoc4 should be loaded each time.

@Devdatta Tengshe 2008-08-14 17:40:24

Thanks for the pointers.

I don't know, whether this is the best approach to the problem or not, but here is how I got it to work. I referenced the Microsoft XML, v2.6 dll in my VBA, and then the following code snippet, gives me the required values

Dim objXML As MSXML2.DOMDocument

    Set objXML = New MSXML2.DOMDocument

    If Not objXML.loadXML(strXML) Then  'strXML is the string with XML'
        Err.Raise objXML.parseError.ErrorCode, , objXML.parseError.reason
    End If

Dim point As IXMLDOMNode
Set point = objXML.firstChild

Debug.Print point.selectSingleNode("X").Text
Debug.Print point.selectSingleNode("Y").Text

@wizlog 2017-08-02 17:42:52

When I try to debug.print one of those points, I get an object variable or With block variable not set. Any suggestions?

Related Questions

Sponsored Content

29 Answered Questions

[SOLVED] How Do You Parse and Process HTML/XML in PHP?

1 Answered Questions

[SOLVED] XML namespace missing for parser

14 Answered Questions

[SOLVED] How do I parse XML in Python?

  • 2009-12-16 05:09:24
  • randombits
  • 1026109 View
  • 837 Score
  • 14 Answer
  • Tags:   python xml

2 Answered Questions

[SOLVED] Import XML into SQL server using OPENXML command with XMLNS

  • 2016-10-22 13:52:41
  • user3129787
  • 399 View
  • 4 Score
  • 2 Answer
  • Tags:   sql sql-server xml

1 Answered Questions

[SOLVED] Add Namespace to an xml root node c#

  • 2016-03-22 05:22:59
  • Dinesh wakti
  • 912 View
  • 0 Score
  • 1 Answer
  • Tags:   c# xml

1 Answered Questions

2 Answered Questions

[SOLVED] JAXB namespace issue with extended annotated class' member

2 Answered Questions

[SOLVED] how to remove namespace and prefix attibutes from a source xml using xslt?

  • 2012-05-24 10:01:35
  • Toseef Zafar
  • 1912 View
  • 1 Score
  • 2 Answer
  • Tags:   xml xslt

1 Answered Questions

Parsing XML in Windows Phone 7

2 Answered Questions

[SOLVED] XML Schema - Key in sequence

Sponsored Content