By benzaita

2008-09-23 21:24:56 8 Comments

Is there an efficient way to tell if a DOM element (in an HTML document) is currently visible (appears in the viewport)?

(The question refers to Firefox)


@JuanM. 2019-03-15 14:06:44

As simpler as it can get IMO:

function isVisible(elem) {
  var coords = elem.getBoundingClientRect();
  return Math.abs( <= coords.height;

@Randy Casburn 2019-03-15 11:32:46

The new Intersection Observer API addresses this question very directly.

This solution will need a polyfill as Safari, Opera and IE don't support this yet. (the polyfill is included in the solution).

In this solution, there is a box out of view that is the target (observed). When it comes into view, the button at the top in the header is hidden. It is shown once the box leaves the view.

const buttonToHide = document.querySelector('button');

const hideWhenBoxInView = new IntersectionObserver((entries) => {
  if (entries[0].intersectionRatio <= 0) { // If not in view = "inherit";
  } else { = "none";

header {
  position: fixed;
  top: 0;
  width: 100vw;
  height: 30px;
  background-color: lightgreen;

.wrapper {
  position: relative;
  margin-top: 600px;

#box {
  position: relative;
  left: 175px;
  width: 150px;
  height: 135px;
  background-color: lightblue;
  border: 2px solid;
<script src=""></script>
  <button>NAVIGATION BUTTON TO HIDE</button>
  <div class="wrapper">
    <div id="box">

@Alon Eitan 2019-03-15 12:06:18

Good implementation, and according to the link in this answer it should work on safari by adding <!DOCTYPE html> to the HTML

@Walf 2013-04-29 02:36:20

I tried Dan's answer however the algebra used to determine the bounds means that the element must be both ≤ the viewport size and completely inside the viewport to get true, easily leading to false negatives. If you want to determine whether an element is in the viewport at all, ryanve's answer is close but the element being tested should overlap the viewport, so try this:

function isElementInViewport(el) {
    var rect = el.getBoundingClientRect();

    return rect.bottom > 0 &&
        rect.right > 0 &&
        rect.left < (window.innerWidth || document.documentElement.clientWidth) /* or $(window).width() */ && < (window.innerHeight || document.documentElement.clientHeight) /* or $(window).height() */;

@ssten 2018-09-28 10:01:57

Here is a function that tells if an element is in visible in the current viewport of a parent element:

function inParentViewport(el, pa) {
    if (typeof jQuery === "function"){
        if (el instanceof jQuery)
            el = el[0];
        if (pa instanceof jQuery)
            pa = pa[0];

    var e = el.getBoundingClientRect();
    var p = pa.getBoundingClientRect();

    return (
        e.bottom >= &&
        e.right >= p.left && <= p.bottom &&
        e.left <= p.right

@Eric Chen 2014-04-23 03:04:03

my shorter and faster version.

function isElementOutViewport(el){
    var rect = el.getBoundingClientRect();
    return rect.bottom < 0 || rect.right < 0 || rect.left > window.innerWidth || > window.innerHeight;

add jsFiddle as required

@Eric Chen 2015-01-19 23:05:19

My solution are more greedy and faster, when element have any pixel in viewport , it's will return false.

@Y.K. 2018-09-05 21:09:25

I like it. Concise. You could remove the spaces between function name and parenthesis, and between parenthesis and brace, on first line. Never liked those spaces. Maybe it's just my Text editor that color codes it all that still makes it easy to read. function aaa(arg){statements} I know that doesn't make it execute faster, falls under minifying instead.

@Eric Chen 2018-09-07 03:58:52

@Y.K. okay, done.

@Andy E 2013-03-04 14:18:08


In modern browsers, you might want to check out the Intersection Observer API which provides the following benefits:

  • Better performance than listening for scroll events
  • Works in cross domain iframes
  • Can tell if an element is obstructing/intersecting another

Intersection Observer is on its way to being a full-fledged standard and is already supported in Chrome 51+, Edge 15+ and Firefox 55+ and is under development for Safari. There's also a polyfill available.

Previous answer

There are some issues with the answer provided by Dan that might make it an unsuitable approach for some situations. Some of these issues are pointed out in his answer near the bottom, that his code will give false positives for elements that are:

  • Hidden by another element in front of the one being tested
  • Outside the visible area of a parent or ancestor element
  • An element or its children hidden by using the CSS clip property

These limitations are demonstrated in the following results of a simple test:

Failed test, using isElementInViewport

The solution: isElementVisible()

Here's a solution to those problems, with the test result below and an explanation of some parts of the code.

function isElementVisible(el) {
    var rect     = el.getBoundingClientRect(),
        vWidth   = window.innerWidth || doc.documentElement.clientWidth,
        vHeight  = window.innerHeight || doc.documentElement.clientHeight,
        efp      = function (x, y) { return document.elementFromPoint(x, y) };     

    // Return false if it's not in the viewport
    if (rect.right < 0 || rect.bottom < 0 
            || rect.left > vWidth || > vHeight)
        return false;

    // Return true if any of its four corners are visible
    return (
      ||  el.contains(efp(rect.right,
      ||  el.contains(efp(rect.right, rect.bottom))
      ||  el.contains(efp(rect.left,  rect.bottom))

Passing test:

And the result:

Passed test, using isElementVisible

Additional notes

This method is not without its own limitations, however. For instance, an element being tested with a lower z-index than another element at the same location would be identified as hidden even if the element in front doesn't actually hide any part of it. Still, this method has its uses in some cases that Dan's solution doesn't cover.

Both element.getBoundingClientRect() and document.elementFromPoint() are part of the CSSOM Working Draft specification and are supported in at least IE 6 and later and most desktop browsers for a long time (albeit, not perfectly). See Quirksmode on these functions for more information.

contains() is used to see if the element returned by document.elementFromPoint() is a child node of the element we're testing for visibility. It also returns true if the element returned is the same element. This just makes the check more robust. It's supported in all major browsers, Firefox 9.0 being the last of them to add it. For older Firefox support, check this answer's history.

If you want to test more points around the element for visibility―ie, to make sure the element isn't covered by more than, say, 50%―it wouldn't take much to adjust the last part of the answer. However, be aware that it would probably be very slow if you checked every pixel to make sure it was 100% visible.

@Kevin Lamping 2013-03-19 19:34:39

Did you mean to use doc.documentElement.clientWidth? Should that be 'document.documentElement' instead? On a different note, this is the only method the also works for use cases like hiding the content of an element for accessibility using the CSS 'clip' property:‌​ity

@Andy E 2013-03-19 20:14:33

@klamping: good catch, thanks. I'd copied it right out of my code where I was using doc as an alias for document. Yeah, I like to think of this as a decent solution for the edge cases.

@Dan 2013-06-25 15:06:25

Do you have any ideas of fixing z-index problem?

@Christoph 2013-09-10 10:09:26

@Dan actually, elementFromPoint takes care of this...

@Andy E 2013-09-10 12:13:01

@Christoph: although he didn't really make it clear, I assume Dan is talking about the fact that an element may be in front of the one you're checking for, but not hiding (ie, a transparent layer). For this scenario, it's obviously quite difficult to determine whether an element is visible or not, because my solution would give false negatives. It could be modified to return a non-boolean flag, ie. "hidden", "visible" or "indeterminate", however.

@FooBar 2013-11-26 16:20:44

I don't find this working with hide/slideup. When the element has been slided up / hided, the function will not return true.

@Louis 2013-11-26 16:22:14

There's a bug. I rant the fiddle. The results of the tests are Test 1: false and Test 2: true. If I force the algorithm to use compareDocumentPosition by editing the line where contains is set so that it is set to compareDocumentPosition, then the results are Test 1: false, Test 2: false. That's because 0x10 should be bitwise-anded with the result of compareDocumentPosition. Or 0x14 could be used for equality since the specs say a contained node is always following.

@Satya Prakash 2013-12-28 07:05:13

For me it is not working. But inViewport() in previous answer is working in FF.

@Jared 2015-03-10 08:15:42

It may also be beneficial to check that the center of the element is visible if you have rounded corners or a transform applied, as the bounding corners may not return the expected element: element.contains(efp(rect.right - (rect.width / 2), rect.bottom - (rect.height / 2)))

@Schism 2015-06-03 18:39:06

The declaration of efp would be better as efp = document.elementFromPoint.bind(document).

@Andy E 2015-06-03 18:57:23

@schism, only if you don't care about IE8 support (and the fact that bound functions aren't well optimised in some browsers) :-)

@Schism 2015-06-04 15:01:16

@AndyE I guess I'm just privileged to not have to care about it! :-) Incidentally, this seems to work in 4.4 Webview but not Chrome...

@Lewis 2015-06-07 08:46:54

Your solution are more elegant than the most upvoted answer. However, just like the above one, it fails on overflowing elements which are in current viewport but invisible.

@Eric 2015-07-15 19:08:59

I have an odd situation, but I want to note it for future readers. My project is embedded in another via an iframe. The iframe has a scrollbar, because the space allocated to it is larger than is made visible. Neither Dan nor Andy have an approach that works for my situation. Elements off the bottom of the iframe, that you would have to scroll to, count as visible via both approaches. rainyjune, ryanve and ally's answers also gives this false positive. There is no way I have yet found to discover the visible size of the iframe, only the allocated size.

@Rayjax 2016-02-18 14:05:26

Did not work on inputs for me (chrome canary 50). Not sure why, maybe native rounder corners ? I had to reduce the coords slightly to make it work el.contains(efp(rect.left+1, || el.contains(efp(rect.right-1, || el.contains(efp(rect.right-1, rect.bottom-1)) || el.contains(efp(rect.left+1, rect.bottom-1))

@Andy E 2016-02-18 17:36:46

@rayjax it's because the chrome devs decided to change the behaviour of window.innerHeight/Width and break the web, see and feel free to add your complaint to the rest!

@Rayjax 2016-02-19 15:20:41

@AndyE if I am correct, innerHeight/Width would impact only the first part of the function( is inside window) not the second (is visible) ?

@Andy 2016-07-19 19:02:04

@AndyE This wouldn't always work for elements that are wider/taller than the viewport, because all corners could be outside the screen even though it's visible

@Andy 2016-07-19 19:04:11

@AndyE to solve that you could test the corners of the intersection of the element's bounding client rect and the viewport rect

@Andy 2016-07-19 19:10:26

Also elementFromPoint can still return elements with opacity: 0

@Stevan Tosic 2017-06-19 10:49:18

The easy and small solution that has worked for me.

Example You want to see if the element is visible in parent element that has overflow scroll.

$(window).on('scroll', function () {  

     var container = $('#sidebar');
     var containerHeight = container.height();
     var scrollPosition = $('#row1').offset().top - container.offset().top;

     if (containerHeight < scrollPosition) {
         console.log('not visible');
     } else {

@Adam Rehal 2015-01-30 14:49:11

I find that the accepted answer here is overly complicated for most use cases. This code does the job well (using JQuery) and differentiates between fully visible and partially visible elements.

var element         = $("#element");
var topOfElement    = element.offset().top;
var bottomOfElement = element.offset().top + element.outerHeight(true);
var $window         = $(window);

$window.bind('scroll', function() {

    var scrollTopPosition   = $window.scrollTop()+$window.height();
    var windowScrollTop     = $window.scrollTop()

    if( windowScrollTop > topOfElement && windowScrollTop < bottomOfElement) {
       // Element is partially visible (above viewable area)
       console.log("Element is partially visible (above viewable area)");

    }else if( windowScrollTop > bottomOfElement && windowScrollTop > topOfElement ) {
        // Element is hidden (above viewable area)
       console.log("Element is hidden (above viewable area)");

    }else if( scrollTopPosition < topOfElement && scrollTopPosition < bottomOfElement ) {
        // Element is hidden (below viewable area)
        console.log("Element is hidden (below viewable area)");

    }else if( scrollTopPosition < bottomOfElement && scrollTopPosition > topOfElement ) {
        // Element is partially visible (below viewable area)
        console.log("Element is partially visible (below viewable area)");

        // Element is completely visible
        console.log("Element is completely visible");

@noobsharp 2016-05-08 14:45:11

Works brilliantly! Tested on Chrome, Firefox and Safari.

@Jonatas Walker 2016-10-01 12:54:09

You can use this.

@sam 2017-07-01 19:36:57

You should definitely cache $window = $(window) outside the scroll handler.

@r3wt 2015-08-02 13:40:44

I found it troubling that there wasn't a jQuery centric version of the functionality available. When i came across Dan's solution i spied the opportunity to provide something for folks who like to program in the jQuery OO style. Be sure to scroll up and leave an upvote on Dan's code. Its nice and snappy and works like a charm for me.

bada bing bada boom

$.fn.inView = function(){
    if(!this.length) return false;
    var rect = this.get(0).getBoundingClientRect();

    return ( >= 0 &&
        rect.left >= 0 &&
        rect.bottom <= (window.innerHeight || document.documentElement.clientHeight) &&
        rect.right <= (window.innerWidth || document.documentElement.clientWidth)


//additional examples for other use cases
//true false whether an array of elements are all in view
$.fn.allInView = function(){
    var all = [];
        all.push( $(this).inView() );
    return all.indexOf(false) === -1;

//only the class elements in view
    return $(this).inView();

//only the class elements not in view
    return !$(this).inView();



    if( $('footer').inView() ) {
        // do cool stuff


@calasyr 2016-05-24 23:58:53

Would the curly brace be sufficient to close the if statement?

@The Whiz of Oz 2017-06-20 07:38:09

I could not make it work with multiple elements of an identical class.

@r3wt 2017-06-20 20:07:45

@TheWhizofOz i've updated my answer to give examples of the other possible use cases you've brought up. best of luck.

@Dan 2011-09-26 15:27:32

Now most browsers support getBoundingClientRect method, which has become the best practice. Using an old answer is very slow, not accurate and has several bugs.

The solution selected as correct is almost never precise. You can read more about its bugs.

This solution was tested on IE7+, iOS5+ Safari, Android2+, Blackberry, Opera Mobile, and IE Mobile 10.

function isElementInViewport (el) {

    //special bonus for those using jQuery
    if (typeof jQuery === "function" && el instanceof jQuery) {
        el = el[0];

    var rect = el.getBoundingClientRect();

    return ( >= 0 &&
        rect.left >= 0 &&
        rect.bottom <= (window.innerHeight || document.documentElement.clientHeight) && /*or $(window).height() */
        rect.right <= (window.innerWidth || document.documentElement.clientWidth) /*or $(window).width() */

How to use:

You can be sure that the function given above returns correct answer at the moment of time when it is called, but what about tracking element's visibility as an event?

Place the following code at the bottom of your <body> tag:

function onVisibilityChange(el, callback) {
    var old_visible;
    return function () {
        var visible = isElementInViewport(el);
        if (visible != old_visible) {
            old_visible = visible;
            if (typeof callback == 'function') {

var handler = onVisibilityChange(el, function() {
    /* your code go here */

$(window).on('DOMContentLoaded load resize scroll', handler); 

/* //non-jQuery
if (window.addEventListener) {
    addEventListener('DOMContentLoaded', handler, false); 
    addEventListener('load', handler, false); 
    addEventListener('scroll', handler, false); 
    addEventListener('resize', handler, false); 
} else if (window.attachEvent)  {
    attachEvent('onDOMContentLoaded', handler); // IE9+ :(
    attachEvent('onload', handler);
    attachEvent('onscroll', handler);
    attachEvent('onresize', handler);

If you do any DOM modifications, they can change your element's visibility of course.

Guidelines and common pitfalls:

Maybe you need to track page zoom / mobile device pinch? jQuery should handle zoom/pinch cross browser, otherwise first or second link should help you.

If you modify DOM, it can affect the element's visibility. You should take control over that and call handler() manually. Unfortunately, we have no cross browser onrepaint event. On the other hand that allows us to make optimizations and perform re-check only on DOM modifications that can change element's visibility.

Never Ever use it inside jQuery $(document).ready() only, because there is no warranty CSS has been applied in this moment. Your code can work locally with your CSS on hard drive, but once put on remote server it will fail.

After DOMContentLoaded is fired, styles are applied, but the images are not loaded yet. So, we should add window.onload event listener.

We can't catch zoom/pinch event yet.

The last resort could be the following code:

/* TODO: this looks like a very bad code */
setInterval(handler, 600); 

You can use awesome feature pageVisibiliy HTML5 API if you care if the tab with your web page is active and visible.

TODO: this method does not handle two situations:

@Claudio 2011-10-20 12:38:21

I'm using this solution (beware the "botom" typo, though). There is also something to be aware of, when the element we're considering would have images into it. Chrome (at least) must wait for the image to be loaded to have the exact value for the boundingRectangle. Seems that Firefox does not have this "problem"

@Joe Strommen 2012-03-30 14:47:32

window.innerHeight and innerWidth are undefined in IE. There's a good article at showing the various ways to get the document height...document.body.clientHeight seems to be the best way overall. I've edited your answer accordingly.

@Matas Petrikas 2012-04-04 10:41:53

here's my version of the check, it just checks if the element is visible in vp at all:

@Andy E 2013-03-04 13:42:51

If you don't need to support IE 5.5 and lower (which you probably don't), you can use (window.innerWidth || document.documentElement.clientWidth) and the height equivalents for a cross browser solution.

@Dan 2013-04-03 18:38:33

@Claudio: the problem is that page is REPAINTED after each picture is loaded. So, if you call my function before the picture comes, you get a correct result, but it's valid for a few milliseconds until the picture apears and the container gets extended

@Dan 2013-06-05 09:47:44

@MatasPetrikas your version has mistakes, but you've been fixed in comments

@Kevin B 2013-10-28 15:22:29

$(document).on('ready', why....

@Nobita 2013-10-30 16:58:03

Why that space after document. , in "rect.bottom <= (window.innerHeight || document. documentElement.clientHeight)" ??

@agaase 2013-12-08 09:04:08

Does it work when you have scrolling enabled in a container inside body. For e.g it doesn't work here - isElementInViewport(document.getElementById("innerele")). innerele is present inside a container which has scrolling enabled.

@Satya Prakash 2013-12-28 07:09:04

Do I need to use all these DOMContentLoaded load resize scroll? Any performance issue etc!

@Satya Prakash 2013-12-28 11:44:12

I see it is not working on other element jQuery(window).on than on window but I see handler is called MANY times on every scroll. Is there a way to tie the event on particular element?

@Roonaan 2014-02-21 07:29:22

The calculations assume that the element is smaller than the screen. If you have high or wide elements, it might be more accurate to use return (rect.bottom >= 0 && rect.right >= 0 && <= (window.innerHeight || document.documentElement.clientHeight) && rect.left <= (window.innerWidth || document.documentElement.clientWidth));

@jiminy 2014-04-12 07:44:11

Tip: To those trying to implement this with jQuery, just a friendly reminder to pass in the HTML DOM object (e.g., isElementInViewport(document.getElementById('elem'))) and not the jQuery object (e.g., isElementInViewport($("#elem))). The jQuery equivalent is to add [0] like so: isElementInViewport($("#elem)[0]).

@Dan 2014-04-14 11:20:50

@RobG 2014-09-11 05:04:28

Brilliant. If not using jQuery, instanceof jQuery throws an error.

@RobG 2014-09-24 06:04:04

@Dan—if (jQuery != undefined) doesn't fix anything, it will still throw a reference error if jQuery hasn't been defined. The way to fix it (i.e. prevent an error if jQuery hasn't been defined or isn't a constructor) is if (typeof jQuery == 'function' && el.instanceof jQuery), which isn't bullet proof (because instanceof isn't particularly useful) but should be good enough.

@rvighne 2014-11-16 16:24:32

You can catch the zoom/pinch event. The resize event is fired when either the window is resized or the page is zoomed.

@Mahn 2015-01-13 19:52:35

Here's my version, supports container elements (e.g. if the element is within another scrollable element) and total or partial visibility (jQuery only though):

@Todd Prouty 2015-05-21 19:44:09

@Mahn — I like your solution, it looks like exactly what I need. Can you give an example of usage? I'm not clear on how to reference that type of function.

@Mahn 2015-05-21 22:30:50

@ToddProuty once declared, you can do $("#elementInside").isInViewport("#parentElement") (returns true if #elementInside is fully visible within #parentElement) or $("#elementInside").isInViewport("#parentElement", true) (returns true if #elementInside is at least partially visible within #parentElement) or $("#elementInside").isInViewport() (returns true if visible within the main window)

@Lewis 2015-06-07 08:44:28

This approach fails on overflowing elements which are in current viewport but invisible.

@RJ Cuthbertson 2015-10-27 19:20:22

At least in the developer tools, in Firefox, getBoundingClientRect() is giving me values just slightly wider than the viewport for elements with width:100%, i.e. the viewport is 815px and the value of "right" is 815.2000122070312. I used Math.floor() on the properties of rect to work around this.

@SuperUberDuper 2015-12-10 12:52:23

How would I use this to get all the visible elements in the current viewport? For bonus I would have the coords relative to the viewport.

@Vernon 2016-04-13 10:17:31

I would like to check for multiple jQuery elements that can be in (or out of) the viewport. This script seems to check for one element only. When multiple elements are in the current viewport, I want to retrieve the last element that's in the current viewport. How could this be done using this script? Or some kind of modification?

@Vernon 2016-04-13 12:04:27

@SuperUberDuper I created a Gist which returns the lowest element in your current viewport. If you just return the visibleElements array in this function you have exactly what you need. See:‌​70

@Alexey Sh. 2016-05-26 20:01:16

does it works when keyboard is shown?

@Donato 2016-08-26 23:33:26

What if you have a collection of elements?

@iPherian 2016-09-21 23:31:41

The algebra for this needs clarifying. It's more like testing whether an element is completely outside the viewport. It returns 'invisible' for elements which are only partially outside the viewport. See @Walf answer for more intuitive version. (of isElementInViewport). The event listening works great.

@M_Willett 2016-10-18 10:47:45

el is not defined

@Corey Alix 2017-01-12 19:35:24

Found this complement function useful for determining when to scroll when it is not visible: function alignToTop(el) { let rect = el.getBoundingClientRect(); return < 0 || rect.bottom <= (window.innerHeight || document.documentElement.clientHeight); }

@svnm 2017-02-03 01:53:50

I have found this to work nearly perfectly, except for extremely fast scrolling, e.g. pressing cmd down or cmd up it can sometimes not be accurate. I have found the alternative is to use which is always 100% accurate for me, and very performant

@matteo 2017-11-25 21:44:46

This has a huge limitation, though. Imagine an SVG node, even as simple as a rectangle, that is rotated, say 45 degrees counterclockwise. Its (original) "left" border, now inclinated 45 degrees, can easily be beyond the top-right corner of the viewport, hance having the whole rectangle outside of the viewport, and yet the bounding box will still overlap it.

@Miguel Palau 2018-04-05 21:54:17

const onVisibilityChange = (el, callback) => () => isElementInViewport(el) && callback()

@Jezzamon 2018-08-26 06:01:35

This answer checks if an element is entirely displayed in the viewport. If part of it is cut-off, this will treat it as not displayed. If you want to know is any part of the element is visible, use the snippet from @Roonaan's comment

@Robert Molina 2018-12-25 20:52:14

Hey, I think it might be worth to add if (!el) { return; } to avoid crashes, just in case.

@Sander Jonk 2017-01-13 06:57:09

I use this function (it only checks if the y is inscreen since most of the time the x is not needed)

function elementInViewport(el) {
    var elinfo = {

    if ( + elinfo.height < window.pageYOffset || > window.pageYOffset + window.innerHeight) {
        return false;
    } else {
        return true;


@Domysee 2016-06-23 17:47:56

All answers I've encountered here only check if the element is positioned inside the current viewport. But that doesn't mean that it is visible.
What if the given element is inside a div with overflowing content, and it is scrolled out of view?

To solve that, you'd have to check if the element is contained by all parents.
My solution does exactly that:

It also allows you to specify how much of the element has to be visible.

Element.prototype.isVisible = function(percentX, percentY){
    var tolerance = 0.01;   //needed because the rects returned by getBoundingClientRect provide the position up to 10 decimals
    if(percentX == null){
        percentX = 100;
    if(percentY == null){
        percentY = 100;

    var elementRect = this.getBoundingClientRect();
    var parentRects = [];
    var element = this;

    while(element.parentElement != null){
        element = element.parentElement;

    var visibleInAllParents = parentRects.every(function(parentRect){
        var visiblePixelX = Math.min(elementRect.right, parentRect.right) - Math.max(elementRect.left, parentRect.left);
        var visiblePixelY = Math.min(elementRect.bottom, parentRect.bottom) - Math.max(,;
        var visiblePercentageX = visiblePixelX / elementRect.width * 100;
        var visiblePercentageY = visiblePixelY / elementRect.height * 100;
        return visiblePercentageX + tolerance > percentX && visiblePercentageY + tolerance > percentY;
    return visibleInAllParents;

This solution ignored the fact that elements may not be visible due to other facts, like opacity: 0.

I have tested this solution in Chrome and Internet Explorer 11.

@Philzen 2016-03-14 13:14:21

For a similar challenge i really enjoyed this gist which exposes a polyfill for scrollIntoViewIfNeeded().

All the necessary Kung Fu needed to answer is within this block:

var parent = this.parentNode,
    parentComputedStyle = window.getComputedStyle(parent, null),
    parentBorderTopWidth = parseInt(parentComputedStyle.getPropertyValue('border-top-width')),
    parentBorderLeftWidth = parseInt(parentComputedStyle.getPropertyValue('border-left-width')),
    overTop = this.offsetTop - parent.offsetTop < parent.scrollTop,
    overBottom = (this.offsetTop - parent.offsetTop + this.clientHeight - parentBorderTopWidth) > (parent.scrollTop + parent.clientHeight),
    overLeft = this.offsetLeft - parent.offsetLeft < parent.scrollLeft,
    overRight = (this.offsetLeft - parent.offsetLeft + this.clientWidth - parentBorderLeftWidth) > (parent.scrollLeft + parent.clientWidth),
    alignWithTop = overTop && !overBottom;

this refers to the element that you want to know if it is i.e. overTop or overBottom - just should get the drift...

@www139 2015-09-13 13:59:36

I had the same question and figured it out by using getBoundingClientRect(). This code is completely 'generic' and only has to be written once for it to work (you don't have to write it out for each element that you want to know is in the viewport). This code only checks to see if it is vertically in the viewport not horizontally. In this case, the variable (array) 'elements' holds all the elements that you are checking to be vertically in the viewport, so grab any elements you want anywhere and store them there. The 'for loop', loops through each element and checks to see if it is vertically in the viewport. This code executes every time the user scrolls! If the getBoudingClientRect().top is less than 3/4 the viewport (the element is one quarter in the viewport), it registers as 'in the viewport'. Since the code is generic, you will want to know 'which' element is in the viewport. To find that out, you can determine it by custom attribute, node name, id, class name, and more. Here is my code (Tell me if it doesn't work, it has been tested in IE 11, FireFox 40.0.3, Chrome Version 45.0.2454.85 m, Opera 31.0.1889.174, and Edge with Windows 10, [not Safari yet])...

//scrolling handlers...
window.onscroll = function(){
  var elements = document.getElementById('whatever').getElementsByClassName('whatever');
  for(var i = 0; i != elements.length; i++)
   if(elements[i].getBoundingClientRect().top <= window.innerHeight*0.75 && elements[i].getBoundingClientRect().top > 0)
      console.log(elements[i].nodeName + ' ' + elements[i].className + ' ' + elements[i].id + ' is in the viewport; proceed with whatever code you want to do here.');

Hope this helps someone :-)

@ton 2015-04-24 15:12:46

I think this is a more functional way to do it. The Dan's answer do not work in recursive context.

This function solve the problem when your element is inside others scrollable divs by testing any levels recursively upper to the HTML tag, and stops in the first false.

 * fullVisible=true only returns true if the all object rect is visible
function isReallyVisible(el, fullVisible) {
    if ( el.tagName == "HTML" )
            return true;
    var parentRect=el.parentNode.getBoundingClientRect();
    var rect = arguments[2] || el.getBoundingClientRect();
    return (
            ( fullVisible ?    >=    : rect.bottom > ) &&
            ( fullVisible ? rect.left   >= parentRect.left   : rect.right  > parentRect.left ) &&
            ( fullVisible ? rect.bottom <= parentRect.bottom :    < parentRect.bottom ) &&
            ( fullVisible ? rect.right  <= parentRect.right  : rect.left   < parentRect.right ) &&
            isReallyVisible(el.parentNode, fullVisible, rect)

@Lumic 2015-01-02 12:17:33

Checks if element is at least partially in view (vertical dimension):

function inView(element) {
                var box = element.getBoundingClientRect();
                return inViewBox(box);

function inViewBox(box) {
                return ((box.bottom < 0) || ( > getWindowSize().h)) ? false : true;

function getWindowSize() { 
        return { w: document.body.offsetWidth || document.documentElement.offsetWidth || window.innerWidth, h: document.body.offsetHeight || document.documentElement.offsetHeight || window.innerHeight} 

@Pirijan 2014-12-26 21:00:32

Based on @dan's solution above (, I had a go at cleaning up implementation so that using it multiple times on the same page is easier:

$(function() {

  $(window).on('load resize scroll', function() {
    addClassToElementInViewport($('.bug-icon'), 'animate-bug-icon');
    addClassToElementInViewport($('.another-thing'), 'animate-thing');
    // 👏 repeat as needed ...

  function addClassToElementInViewport(element, newClass) {
    if (inViewport(element)) {

  function inViewport(element) {
    if (typeof jQuery === "function" && element instanceof jQuery) {
      element = element[0];
    var elementBounds = element.getBoundingClientRect();
    return ( >= 0 &&
      elementBounds.left >= 0 &&
      elementBounds.bottom <= $(window).height() &&
      elementBounds.right <= $(window).width()


The way I'm using it is that when the element scrolls into view, I'm adding a class that triggers a css keyframe animation. It's pretty straightforward and works especially well when you've got like 10+ things to conditionally animate on a page.

Hope it helps!

@Adam Rehal 2017-11-01 08:13:08

You should definitely cache $window = $(window) outside the scroll handler

@Stefan Steiger 2014-09-25 12:54:30

As a public service:
Dan's answer with the correct calculations (element can be > window, especially on mobile phone screens), and correct jQuery testing, as well as adding isElementPartiallyInViewport:

By the way, the difference between window.innerWidth and document.documentElement.clientWidth is that clientWidth/clientHeight doesn't include the scrollbar, while window.innerWidth/Height does.

function isElementPartiallyInViewport(el)
    //special bonus for those using jQuery
    if (typeof jQuery !== 'undefined' && el instanceof jQuery) el = el[0];

    var rect = el.getBoundingClientRect();
    // DOMRect { x: 8, y: 8, width: 100, height: 100, top: 8, right: 108, bottom: 108, left: 8 }
    var windowHeight = (window.innerHeight || document.documentElement.clientHeight);
    var windowWidth = (window.innerWidth || document.documentElement.clientWidth);

    var vertInView = ( <= windowHeight) && (( + rect.height) >= 0);
    var horInView = (rect.left <= windowWidth) && ((rect.left + rect.width) >= 0);

    return (vertInView && horInView);

function isElementInViewport (el) 
    //special bonus for those using jQuery
    if (typeof jQuery !== 'undefined' && el instanceof jQuery) el = el[0];

    var rect = el.getBoundingClientRect();
    var windowHeight = (window.innerHeight || document.documentElement.clientHeight);
    var windowWidth = (window.innerWidth || document.documentElement.clientWidth);

    return (
           (rect.left >= 0)
        && ( >= 0)
        && ((rect.left + rect.width) <= windowWidth)
        && (( + rect.height) <= windowHeight)


function fnIsVis(ele)
    var inVpFull = isElementInViewport(ele);
    var inVpPartial = isElementPartiallyInViewport(ele);
    console.log("Fully in viewport: " + inVpFull);
    console.log("Partially in viewport: " + inVpPartial);


<!DOCTYPE html>
<html lang="en">
    <meta charset="utf-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <meta name="description" content="">
    <meta name="author" content="">
    <script src=""></script>    
    <script src="scrollMonitor.js"></script>

    <script type="text/javascript">

        function isElementPartiallyInViewport(el)
            //special bonus for those using jQuery
            if (typeof jQuery !== 'undefined' && el instanceof jQuery) el = el[0];

            var rect = el.getBoundingClientRect();
            // DOMRect { x: 8, y: 8, width: 100, height: 100, top: 8, right: 108, bottom: 108, left: 8 }
            var windowHeight = (window.innerHeight || document.documentElement.clientHeight);
            var windowWidth = (window.innerWidth || document.documentElement.clientWidth);

            var vertInView = ( <= windowHeight) && (( + rect.height) >= 0);
            var horInView = (rect.left <= windowWidth) && ((rect.left + rect.width) >= 0);

            return (vertInView && horInView);

        function isElementInViewport (el) 
            //special bonus for those using jQuery
            if (typeof jQuery !== 'undefined' && el instanceof jQuery) el = el[0];

            var rect = el.getBoundingClientRect();
            var windowHeight = (window.innerHeight || document.documentElement.clientHeight);
            var windowWidth = (window.innerWidth || document.documentElement.clientWidth);

            return (
                   (rect.left >= 0)
                && ( >= 0)
                && ((rect.left + rect.width) <= windowWidth)
                && (( + rect.height) <= windowHeight)


        function fnIsVis(ele)
            var inVpFull = isElementInViewport(ele);
            var inVpPartial = isElementPartiallyInViewport(ele);
            console.log("Fully in viewport: " + inVpFull);
            console.log("Partially in viewport: " + inVpPartial);

        // var scrollLeft = (window.pageXOffset !== undefined) ? window.pageXOffset : (document.documentElement || document.body.parentNode || document.body).scrollLeft,
        // var scrollTop = (window.pageYOffset !== undefined) ? window.pageYOffset : (document.documentElement || document.body.parentNode || document.body).scrollTop;



    <div style="display: block; width: 2000px; height: 10000px; background-color: green;">

        <br /><br /><br /><br /><br /><br />
        <br /><br /><br /><br /><br /><br />
        <br /><br /><br /><br /><br /><br />

        <input type="button" onclick="fnIsVis(document.getElementById('myele'));" value="det" />

        <br /><br /><br /><br /><br /><br />
        <br /><br /><br /><br /><br /><br />
        <br /><br /><br /><br /><br /><br />

        <div style="background-color: crimson; display: inline-block; width: 800px; height: 500px;" ></div>
        <div id="myele" onclick="fnIsVis(this);" style="display: inline-block; width: 100px; height: 100px; background-color: hotpink;">

        <br /><br /><br /><br /><br /><br />
        <br /><br /><br /><br /><br /><br />
        <br /><br /><br /><br /><br /><br />

        <input type="button" onclick="fnIsVis(document.getElementById('myele'));" value="det" />


    <script type="text/javascript">

        var element = document.getElementById("myele");
        var watcher = scrollMonitor.create( element );


        watcher.stateChange(function() {
            console.log("state changed");
            // $(element).toggleClass('fixed', this.isAboveViewport)


@RJ Cuthbertson 2015-10-28 13:02:58

isElementPartiallyInViewport is very useful as well. Nice one.

@Arun chauhan 2018-08-13 08:00:04

For isElementInViewport(e) : Your code is not even loading images, This one is correct : function isElementInViewport(e) { var t = e.getBoundingClientRect(); return >= 0 && t.left >= 0 && t.bottom <= (window.innerHeight || document.documentElement.clientHeight) && t.right <= (window.innerWidth || document.documentElement.clientWidth) }

@Stefan Steiger 2018-08-13 08:53:27

@Arun chauhan: None of my code is loading images, so why should it, and the formula is correct.

@targumon 2019-01-22 10:29:45

@StefanSteiger Many answers here contain window.innerHeight || document.documentElement.clientHeight as part of the check. Since you're the first to refer to the difference between them, maybe you can also explain why even bother with this fallback? AFAIK window.innerHeight will always have a value (can't be null or undefined) so the only falsy value it can hold is 0. Which seems like a real edge case in which I'm not even sure how document.documentElement.clientWidth is suddenly helpful.

@Stefan Steiger 2019-01-22 16:38:45

@targumon: The reason is support of old browsers.

@targumon 2019-01-23 23:31:50

@StefanSteiger according to MDN it's supported since IE9 so it's practically safe (at least in my case) to just use window.innerHeight directly. Thanks!

@Stefan Steiger 2019-01-25 12:09:26

@targumon: Yea, but that means not in IE8.

@Ally 2014-02-07 11:39:43

Here's my solution, it will work if an element is hidden inside a scroll-able container.

Here's a demo (try re-sizing the window to)

var visibleY = function(el){
    var top = el.getBoundingClientRect().top, rect, el = el.parentNode;
    do {
        rect = el.getBoundingClientRect();
        if (top <= rect.bottom === false)
            return false;
        el = el.parentNode;
    } while (el != document.body);
    // Check its within the document viewport
    return top <= document.documentElement.clientHeight;

I only needed to check if it's visible in the Y axis (for a scrolling ajax load more records feature).

@Prestaul 2008-09-24 02:40:09

Update: Time marches on and so have our browsers. This technique is no longer recommended and you should use @Dan's solution below ( if you do not need to support IE<7.

Original solution (now outdated):

This will check if the element is entirely visible in the current viewport:

function elementInViewport(el) {
  var top = el.offsetTop;
  var left = el.offsetLeft;
  var width = el.offsetWidth;
  var height = el.offsetHeight;

  while(el.offsetParent) {
    el = el.offsetParent;
    top += el.offsetTop;
    left += el.offsetLeft;

  return (
    top >= window.pageYOffset &&
    left >= window.pageXOffset &&
    (top + height) <= (window.pageYOffset + window.innerHeight) &&
    (left + width) <= (window.pageXOffset + window.innerWidth)

You could modify this simply to determine if any part of the element is visible in the viewport:

function elementInViewport2(el) {
  var top = el.offsetTop;
  var left = el.offsetLeft;
  var width = el.offsetWidth;
  var height = el.offsetHeight;

  while(el.offsetParent) {
    el = el.offsetParent;
    top += el.offsetTop;
    left += el.offsetLeft;

  return (
    top < (window.pageYOffset + window.innerHeight) &&
    left < (window.pageXOffset + window.innerWidth) &&
    (top + height) > window.pageYOffset &&
    (left + width) > window.pageXOffset

@Prestaul 2008-09-24 02:56:44

Original function posted had a mistake. Needed to save the width/height before reassigning el...

@Prestaul 2008-09-24 03:01:57

It also might be wise to abstract this a bit and create some utility functions. I use one called getViewport that returns the top/left/bottom/right of the visible window, and one called getPosition that finds the top/left of an element.

@MatrixFrog 2010-09-23 00:20:49

I'm trying to get this functionality in a Firefox extension, so just in case someone else is in the same situation... (Web developers, you can of course ignore this comment entirely) This function works perfectly in that context, EXCEPT that window refers to the wrong object, so just put var window = el.ownerDocument.defaultView at the top of the function and you're good to go.

@amartynov 2011-03-06 08:42:26

What if the element lives in a scrollable div and scrolled out of a view??

@Dan 2011-09-26 15:29:17

Please review a newer version of the script below

@Brian 2011-11-15 21:50:49

In a Firefox extension, el.ownerDocument.defaultView.innerWidth is not an accurate representation of the viewport (though neither is window). For example, it will be wrong if you make your firefox window narrower than the widest installed toolbar.

@Eric Nguyen 2012-11-07 23:51:04

Also curious about @amartynov's question. Anyone know how to simply tell if an element is hidden due to overflow of an ancestor element? Bonus if this can be detected regardless of how deeply nested the child is.

@deadManN 2015-07-05 13:45:16

i'm wonder why you recommend below answer while it's pure javascript, and does not seem to use any thing unsupported

@Prestaul 2015-07-06 15:25:11

@deadManN recursing through the DOM is notoriously slow. That is reason enough, but the browser vendors have also created getBoundingClientRect for specifically the purpose of finding element coordinates... Why wouldn't we use it?

@evpozdniakov 2015-11-24 20:47:26

The function works fine if there are not blocks with scrollbars. I suggest to modify while block and the final check: while(elm.offsetParent) {elm = elm.offsetParent; top += elm.offsetTop - elm.scrollTop; left += elm.offsetLeft - elm.scrollLeft; } return (top < (window.innerHeight) && left < (window.innerWidth) && (top + height) > 0 && (left + width) > 0 );

@George 2017-11-09 19:13:48

I suggest adding… although it doesn't support IE11, so you have to use fallback method.

@rainyjune 2013-02-08 08:57:41

A better solution:

function getViewportSize(w) {
    var w = w || window;
    if(w.innerWidth != null) return {w:w.innerWidth, h:w.innerHeight};
    var d = w.document;
    if (document.compatMode == "CSS1Compat") {
        return {
            w: d.documentElement.clientWidth,
            h: d.documentElement.clientHeight
    return { w: d.body.clientWidth, h: d.body.clientWidth };
function isViewportVisible(e) {
    var box = e.getBoundingClientRect();
    var height = box.height || (box.bottom -;
    var width = box.width || (box.right - box.left);
    var viewport = getViewportSize();
    if(!height || !width) return false;
    if( > viewport.h || box.bottom < 0) return false;
    if(box.right < 0 || box.left > viewport.w) return false;
    return true;    

@Andy E 2013-03-04 13:46:48

You should try and explain why your version is better. As it stands, it looks more or less the same as the other solutions.

@teter 2015-05-13 09:10:18

Great solution it has a BOX/ScrollContainer and is not using the WINDOW (only if its not specified). Take a look at the code than rate it is a more universal solution (Was searching for it a lot)

@ryanve 2012-09-14 05:49:34

See the source of verge, which uses getBoundingClientRect. It's like:

function inViewport (el) {

    var r, html;
    if ( !el || 1 !== el.nodeType ) { return false; }
    html = document.documentElement;
    r = el.getBoundingClientRect();

    return ( !!r 
      && r.bottom >= 0 
      && r.right >= 0 
      && <= html.clientHeight 
      && r.left <= html.clientWidth 


Returns true if any part of the element is in the viewport.

@Yuri Salimovskiy 2010-05-03 17:00:34

There is jQuery plugin called inview that does the job

@mmmeff 2014-01-27 23:51:13

My team ran into some serious performance issues with this plugin so I went a head and forked it, changing the implementation to make use of getBoundingClientRect(). Check it out here:

@Jonatas Walker 2016-10-01 13:33:37

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