By Walker

2011-04-23 22:17:18 8 Comments

I have an array of numbers and I'm using the .push() method to add elements to it.

Is there a simple way to remove a specific element from an array?

I'm looking for the equivalent of something like:


I have to use core JavaScript. Frameworks are not allowed.


@Abdelrhman Arnos 2020-08-14 19:11:43

In ES6, the Set collection provides a delete method to delete a specific value from the array, then convert the Set collection to an array by spread operator.

function deleteItem(list, val) {
    const set = new Set(list);
    return [...set];

const letters = ['A', 'B', 'C', 'D', 'E'];
console.log(deleteItem(letters, 'C')); // ['A', 'B', 'D', 'E']

@Flavio Copes 2018-05-04 05:17:29

Here are a few ways to remove an item from an array using JavaScript.

All the method described do not mutate the original array, and instead create a new one.

If you know the index of an item

Suppose you have an array, and you want to remove an item in position i.

One method is to use slice():

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const i = 3
const filteredItems = items.slice(0, i).concat(items.slice(i+1, items.length))


slice() creates a new array with the indexes it receives. We simply create a new array, from start to the index we want to remove, and concatenate another array from the first position following the one we removed to the end of the array.

If you know the value

In this case, one good option is to use filter(), which offers a more declarative approach:

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const valueToRemove = 'c'
const filteredItems = items.filter(item => item !== valueToRemove)


This uses the ES6 arrow functions. You can use the traditional functions to support older browsers:

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const valueToRemove = 'c'
const filteredItems = items.filter(function(item) {
  return item !== valueToRemove


or you can use Babel and transpile the ES6 code back to ES5 to make it more digestible to old browsers, yet write modern JavaScript in your code.

Removing multiple items

What if instead of a single item, you want to remove many items?

Let's find the simplest solution.

By index

You can just create a function and remove items in series:

const items = ['a', 'b', 'c', 'd', 'e', 'f']

const removeItem = (items, i) =>
  items.slice(0, i-1).concat(items.slice(i, items.length))

let filteredItems = removeItem(items, 3)
filteredItems = removeItem(filteredItems, 5)
//["a", "b", "c", "d"]


By value

You can search for inclusion inside the callback function:

const items = ['a', 'b', 'c', 'd', 'e', 'f']
const valuesToRemove = ['c', 'd']
const filteredItems = items.filter(item => !valuesToRemove.includes(item))
// ["a", "b", "e", "f"]


Avoid mutating the original array

splice() (not to be confused with slice()) mutates the original array, and should be avoided.

(originally posted on my site

@karthicvel 2020-07-25 08:50:29

Using .indexOf() and .splice() - Mutable Pattern

There are two scenarios here:

  1. we know the index

const drinks = [ 'Tea', 'Coffee', 'Milk'];
const id = 1;
const removedDrink = drinks.splice(id,  1);

  1. we don’t know the index but know the value.
    const drinks =  ['Tea','Coffee', 'Milk'];
    const id = drinks.indexOf('Coffee'); // 1
    const removedDrink = drinks.splice(id,  1);
    // ["Coffee"]
    // ["Tea", "Milk"]

Using .filter() - Immutable Pattern

The best way you can think about this is - instead of “removing” the item, you’ll be “creating” a new array that just does not include that item. So we must find it, and omit it entirely.

const drinks = ['Tea','Coffee', 'Milk'];
const id = 'Coffee';
const idx = drinks.indexOf(id);
const removedDrink = drinks[idx];
const filteredDrinks = drinks.filter((drink, index) => drink == removedDrink);

console.log("Filtered Drinks Array:"+ filteredDrinks);
console.log("Original Drinks Array:"+ drinks);

@Jeff Noel 2013-08-12 17:56:39

You can do a backward loop to make sure not to screw up the indexes, if there are multiple instances of the element.

var myElement = "chocolate";
var myArray = ['chocolate', 'poptart', 'poptart', 'poptart', 'chocolate', 'poptart', 'poptart', 'chocolate'];

/* Important code */
for (var i = myArray.length - 1; i >= 0; i--) {
  if (myArray[i] == myElement) myArray.splice(i, 1);

Live Demo

@Ahmad 2020-05-31 11:58:03

Immutable way of removing an element from array using ES6 spread operator.

Let's say you want to remove 4.

let array = [1,2,3,4,5]
const index = array.indexOf(4)
let new_array = [...array.slice(0,index), ...array.slice(index+1, array.length)]
=> [1, 2, 3, 5]

@Daniel Waltrip 2020-07-07 00:21:49

An important clarification for new programmers: This does not delete the target item from the array. It creates an entirely new array that is a copy of the original array, except with the target item removed. The word "delete" implies that we are mutating something in place, not making a modified copy.

@Ahmad 2020-07-07 17:26:06

Yes, you are right. This is an immutable way of removing an element. Thanks for clearing this out.

@xavierm02 2011-04-23 22:32:45

It depends on whether you want to keep an empty spot or not.

If you do want an empty slot:

array[index] = undefined;

If you don't want an empty slot:

//To keep the original:
//oldArray = [...array];

//This modifies the array.
array.splice(index, 1);

And if you need the value of that item, you can just store the returned array's element:

var value = array.splice(index, 1)[0];

If you want to remove at either end of the array, you can use array.pop() for the last one or array.shift() for the first one (both return the value of the item as well).

If you don't know the index of the item, you can use array.indexOf(item) to get it (in a if() to get one item or in a while() to get all of them). array.indexOf(item) returns either the index or -1 if not found. 

@Teddy 2020-07-25 10:55:10

It's kinda funny that splice returns another array built out of the removed elements. I wrote something which assumed splice would return the newly modified list (like what immutable collections would do, for example). So, in this particular case of only one item in the list, and that item being removed, the returned list is exactly identical to the original one after splicing that one item. So, my app went into an infinite loop.

@Tom Wadley 2011-04-23 22:23:50

Find the index of the array element you want to remove using indexOf, and then remove that index with splice.

The splice() method changes the contents of an array by removing existing elements and/or adding new elements.

const array = [2, 5, 9];


const index = array.indexOf(5);
if (index > -1) {
  array.splice(index, 1);

// array = [2, 9]

The second parameter of splice is the number of elements to remove. Note that splice modifies the array in place and returns a new array containing the elements that have been removed.

For the reason of completeness, here are functions. The first function removes only a single occurrence (i.e. removing the first match of 5 from [2,5,9,1,5,8,5]), while the second function removes all occurrences:

function removeItemOnce(arr, value) {
  var index = arr.indexOf(value);
  if (index > -1) {
    arr.splice(index, 1);
  return arr;

function removeItemAll(arr, value) {
  var i = 0;
  while (i < arr.length) {
    if (arr[i] === value) {
      arr.splice(i, 1);
    } else {
  return arr;
console.log(removeItemOnce([2,5,9,1,5,8,5], 5))
console.log(removeItemAll([2,5,9,1,5,8,5], 5))

@katma 2020-06-02 16:18:16

Immutable and one-liner way :

const newArr = targetArr.filter(e => e !== elementToDelete);

@Daniel Waltrip 2020-07-07 00:20:26

An important clarification for new programmers: This does not remove the target item from the array. It creates an entirely new array that is a copy of the original array, except with the target item removed.

@mike rodent 2017-11-24 19:17:36

What a shame you have an array of integers, not an object where the keys are string equivalents of these integers.

I've looked through a lot of these answers and they all seem to use "brute force" as far as I can see. I haven't examined every single one, apologies if this is not so. For a smallish array this is fine, but what if you have 000s of integers in it?

Correct me if I'm wrong, but can't we assume that in a key => value map, of the kind which a JavaScript object is, that the key retrieval mechanism can be assumed to be highly engineered and optimised? (NB: if some super-expert tells me that this is not the case, I can suggest using ECMAScript 6's Map class instead, which certainly will be).

I'm just suggesting that, in certain circumstances, the best solution might be to convert your array to an object... the problem being, of course, that you might have repeating integer values. I suggest putting those in buckets as the "value" part of the key => value entries. (NB: if you are sure you don't have any repeating array elements this can be much simpler: values "same as" keys, and just go Object.values(...) to get back your modified array).

So you could do:

const arr = [ 1, 2, 55, 3, 2, 4, 55 ];
const f =    function( acc, val, currIndex ){
    // We have not seen this value before: make a bucket... NB: although val's typeof is 'number',
    // there is seamless equivalence between the object key (always string)
    // and this variable val.
    ! ( val in acc ) ? acc[ val ] = []: 0;
    // Drop another array index in the bucket
    acc[ val ].push( currIndex );
    return acc;
const myIntsMapObj = arr.reduce( f, {});

console.log( myIntsMapObj );


Object [ <1 empty slot>, Array1, Array[2], Array1, Array1, <5 empty slots>, 46 more… ]

It is then easy to delete all the numbers 55.

delete myIntsMapObj[ 55 ]; // Again, although keys are strings this works

You don't have to delete them all: index values are pushed into their buckets in order of appearance, so (for example):

myIntsMapObj[ 55 ].shift(); // And
myIntsMapObj[ 55 ].pop();

will delete the first and last occurrence respectively. You can count frequency of occurrence easily, replace all 55s with 3s by transferring the contents of one bucket to another, etc.

Retrieving a modified int array from your "bucket object" is slightly involved but not so much: each bucket contains the index (in the original array) of the value represented by the (string) key. Each of these bucket values is also unique (each is the unique index value in the original array): so you turn them into keys in a new object, with the (real) integer from the "integer string key" as value... then sort the keys and go Object.values( ... ).

This sounds very involved and time-consuming... but obviously everything depends on the circumstances and desired usage. My understanding is that all versions and contexts of JavaScript operate only in one thread, and the thread doesn't "let go", so there could be some horrible congestion with a "brute force" method: caused not so much by the indexOf ops, but multiple repeated slice/splice ops.

Addendum If you're sure this is too much engineering for your use case surely the simplest "brute force" approach is

const arr = [ 1, 2, 3, 66, 8, 2, 3, 2 ];
const newArray = arr.filter( number => number !== 3 );
console.log( newArray )

(Yes, other answers have spotted Array.prototype.filter...)

@M. Twarog 2020-04-02 10:15:58

ES10 Update

This post summarizes common approaches to element removal from array as of ECMAScript 2019 (ES10).

1. General cases

1.1. Removing Array element by value using .splice()

| In-place: Yes |
| Removes duplicates: Yes(loop), No(indexOf) |
| By value / index: By index |

If you know the value you want to remove from an array you can use the splice method. First you must identify the index of the target item. You then use the index as the start element and remove just one element.

// With a 'for' loop
const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0];
for( let i = 0; i < arr.length; i++){
  if ( arr[i] === 5) {
    arr.splice(i, 1);
} // => [1, 2, 3, 4, 6, 7, 8, 9, 0]

// With the .indexOf() method
const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0];
const i = arr.indexOf(5);
arr.splice(i, 1); // => [1, 2, 3, 4, 6, 7, 8, 9, 0]

1.2. Removing Array element using the .filter() method

| In-place: No |
| Removes duplicates: Yes |
| By value / index: By value |

Specific element can be filtered out from array, by providing filtering function. Such function is then called for every element in array.

const value = 3
let arr = [1, 2, 3, 4, 5, 3]
arr = arr.filter(item => item !== value)
// [ 1, 2, 4, 5 ]

1.3. Removing Array element by extending Array.prototype

| In-place: Yes/No (Depends on implementation) |
| Removes duplicates: Yes/No (Depends on implementation) |
| By value / index: By index / By value (Depends on implementation) |

Prototype of Array can be extended with additional methods. Such methods will be then available to use on created arrays.

Note: Extending prototypes of objects from standard library of JavaScript (like Array) is considered by some as an antipattern.

// In-place, removes all, by value implementation
Array.prototype.remove = function(item) {
    for (let i = 0; i < this.length; i++) {
        if (this[i] === item) {
            this.splice(i, 1);
const arr1 = [1,2,3,1];
arr1.remove(1) // arr1 equals [2,3]

// Non-stationary, removes first, by value implementation
Array.prototype.remove = function(item) {
    const arr = this.slice();
    for (let i = 0; i < this.length; i++) {
        if (arr[i] === item) {
            arr.splice(i, 1);
            return arr;
    return arr;
let arr2 = [1,2,3,1];
arr2 = arr2.remove(1) // arr2 equals [2,3,1]

1.4. Removing Array element using the delete operator

| In-place: Yes |
| Removes duplicates: No |
| By value / index: By index |

Using the delete operator does not affect the length property. Nor does it affect the indexes of subsequent elements. The array becomes sparse, which is a fancy way of saying the deleted item is not removed but becomes undefined.

const arr = [1, 2, 3, 4, 5, 6];
delete arr[4]; // Delete element with index 4
console.log( arr ); // [1, 2, 3, 4, undefined, 6]

The delete operator is designed to remove properties from JavaScript objects, which arrays are objects.

1.5. Removing Array element using Object utilities (>= ES10)

| In-place: No |
| Removes duplicates: Yes |
| By value / index: By value |

ES10 introduced Object.fromEntries, which can be used to create desired Array from any Array-like object and filter unwanted elements during the process.

const object = [1,2,3,4];
const valueToRemove = 3;
const arr = Object.values(Object.fromEntries(
  .filter(([ key, val ]) => val !== valueToRemove)
console.log(arr); // [1,2,4]

2. Special cases

2.1 Removing element if it's at the end of the Array

2.1.1. Changing Array length

| In-place: Yes |
| Removes duplicates: No |
| By value / index: N/A |

JavaScript Array elements can be removed from the end of an array by setting the length property to a value less than the current value. Any element whose index is greater than or equal to the new length will be removed.

const arr = [1, 2, 3, 4, 5, 6];
arr.length = 5; // Set length to remove element
console.log( arr ); // [1, 2, 3, 4, 5]
2.1.2. Using .pop() method

| In-place: Yes |
| Removes duplicates: No |
| By value / index: N/A |

The pop method removes the last element of the array, returns that element, and updates the length property. The pop method modifies the array on which it is invoked, This means unlike using delete the last element is removed completely and the array length reduced.

const arr = [1, 2, 3, 4, 5, 6];
arr.pop(); // returns 6
console.log( arr ); // [1, 2, 3, 4, 5]

2.2. Removing element if it's at the beginning of the Array

| In-place: Yes |
| Removes duplicates: No |
| By value / index: N/A |

The .shift() method works much like the pop method except it removes the first element of a JavaScript array instead of the last. When the element is removed the remaining elements are shifted down.

const arr = [1, 2, 3, 4];
arr.shift(); // returns 1
console.log( arr ); // [2, 3, 4]

2.3. Removing element if it's the only element in the Array

| In-place: Yes |
| Removes duplicates: N/A |
| By value / index: N/A |

The fastest technique is to set an array variable to an empty array.

let arr = [1];
arr = []; //empty array

Alternatively technique from 2.1.1 can be used by setting length to 0.

@Vinod Kumar 2019-10-14 08:38:44

Remove the particular array item

Enter image description here

var cars = ["Apple", "Banana", "Mango", "Orange", "Grapes"];

document.getElementById("demo").innerHTML = cars;

for( var i = 0; i < cars.length; i++){
   if ( cars[i] === "Banana") {
     cars.splice(i, 1);

document.getElementById("demo2").innerHTML =  cars;
p {
  font-size: 20px;
  padding: 10px;
  border: 1px dashed tan;
  color: brown;
<!DOCTYPE html>

<p id="demo"></p>
<p id="demo2"></p>

@hailong 2017-07-30 22:55:52

I post my code that removes an array element in place, and reduce the array length as well.

function removeElement(idx, arr) {
    // Check the index value
    if (idx < 0 || idx >= arr.length) {
    // Shift the elements
    for (var i = idx; i > 0; --i) {
        arr[i] = arr[i - 1];
    // Remove the first element in array

@NullPointer 2013-10-08 10:09:53

I also ran into the situation where I had to remove an element from Array. .indexOf was not working in Internet Explorer, so I am sharing my working jQuery.inArray() solution:

var index = jQuery.inArray(val, arr);
if (index > -1) {
    arr.splice(index, 1);

@Henry Heleine 2014-12-09 22:15:23

jQuery is always good for taking care of any cross-browser compatibility issues of the different JavaScript APIs.

@Don Vincent Preziosi 2013-09-26 00:12:44

Array.prototype.removeItem = function(a) {
    for (i = 0; i < this.length; i++) {
        if (this[i] == a) {
            for (i2 = i; i2 < this.length - 1; i2++) {
                this[i2] = this[i2 + 1];
            this.length = this.length - 1

var recentMovies = ['Iron Man', 'Batman', 'Superman', 'Spiderman'];

@Max Alexander Hanna 2019-01-08 14:34:36

Removing a particular element/string from an array can be done in a one-liner:

theArray.splice(theArray.indexOf("stringToRemoveFromArray"), 1);


theArray : the array you want to remove something particular from

stringToRemoveFromArray : the string you want removed and 1 is the amount of elements you want to remove.

NOTE : If "stringToRemoveFromArray" is not located your in array, this will remove last element of array.

Its always good practice to check if the element exists in your array first, before removing it.

if (theArray.indexOf("stringToRemoveFromArray") >= 0){
   theArray.splice(theArray.indexOf("stringToRemoveFromArray"), 1);

If you have access to newer Ecmascript versions on your client's computers (WARNING, may not work on older stations):

var array=['1','2','3','4','5','6']
var newArray = array.filter((value)=>value!='3');

Where '3' is the value you want removed from the array. The array would then become : ['1','2','4','5','6']

@jdavid05 2019-04-03 11:52:46

This is the answer that worked for me when trying to update an array based on radio button toggling.

@Fusion 2019-04-06 23:35:39

Beware, if "stringToRemoveFromArray" is not located your in array, this will remove last element of array.

@Kinslert Virguez. 2019-09-17 22:49:59

You can create an index with an all accessors example:

<div >

function getIndex($id){
  return (
    alert("This element was removed")

function removeIndex(){
   const index = $id; // You can use splice for slice index on
                                    // accessor id and return with message
            { accesors => {
                <li type="hidden"></li>


    <form id="form" method="post">
        <input  id="{}">
        <input type="submit" callbackforApplySend...getIndex({}) name="sendendform" value="removeIndex" >

@pritam 2019-10-02 07:36:39

Most of the answers here give a solution using -

  1. indexOf and splice
  2. delete
  3. filter
  4. regular for loop

Although all the solutions should work with these methods, I thought we could use string manipulation.

Points to note about this solution -

  1. It will leave holes in the data (they could be removed with an extra filter)
  2. This solution works for not just primitive search values, but also objects.

The trick is to -

  1. stringify input data set and the search value
  2. replace the search value in the input data set with an empty string
  3. return split data on delimiter ,.
    remove = (input, value) => {
        const stringVal = JSON.stringify(value);
        const result = JSON.stringify(input)

        return result.replace(stringVal, "").split(",");

A JSFiddle with tests for objects and numbers is created here -

Check the remove method in the fiddle.

@Stefan Fabian 2020-03-13 13:38:07

So, what exactly is the advantage of this method? What I see is that it's a terribly inefficient and error-prone method of performing a simple task. The result is not parsed again so it returns an array of strings instead of the input type. Even if it was parsed, on arrays of objects it would remove all function members. I don't see any good reason to ever do something like that but given that there are two people who thought this was a good idea, there must be something I'm missing.

@Ajay Thakur 2019-11-04 05:10:50

You can create a prototype for that. Just pass the array element and the value which you want to remove from the array element:

Array.prototype.removeItem = function(array,val) {
    array.forEach((arrayItem,index) => {
        if (arrayItem == val) {
            array.splice(index, 1);
    return array;
var DummyArray = [1, 2, 3, 4, 5, 6];
console.log(DummyArray.removeItem(DummyArray, 3));

@Taylor Hawkes 2019-11-06 20:25:28

To find and remove a particular string from an array of strings:

var colors = ["red","blue","car","green"];
var carIndex = colors.indexOf("car"); // Get "car" index
// Remove car from the colors array
colors.splice(carIndex, 1); // colors = ["red", "blue", "green"]


@Kamil Kiełczewski 2019-12-09 16:04:13


Today (2019-12-09) I conduct performance tests on macOS v10.13.6 (High Sierra) for chosen solutions. I show delete (A), but I not use it in comparison with other methods, because it left empty space in the array.

The conclusions

  • the fastest solution is array.splice (C) (except Safari for small arrays where it has the second time)
  • for big arrays, array.slice+splice (H) is the fastest immutable solution for Firefox and Safari; Array.from (B) is fastest in Chrome
  • mutable solutions are usually 1.5x-6x faster than immutable
  • for small tables on Safari, surprisingly the mutable solution (C) is slower than the immutable solution (G)


In tests I remove middle element from the array in different ways. The A, C solutions are in-place. The B, D, E, F, G, H solutions are immutable.

Results for array with 10 elements

Enter image description here

In Chrome the array.splice (C) is the fastest in-place solution. The array.filter (D) is the fastest immutable solution. The slowest is array.slice (F). You can perform the test on your machine here.

Results for array with 1.000.000 elements

Enter image description here

In Chrome the array.splice (C) is the fastest in-place solution (the delete (C) is similar fast - but it left an empty slot in the array (so it does not perform a 'full remove')). The array.slice-splice (H) is the fastest immutable solution. The slowest is array.filter (D and E). You can perform the test on your machine here.

var a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9];
var log = (letter,array) => console.log(letter, array.join `,`);

function A(array) {
  var index = array.indexOf(5);
  delete array[index];
  log('A', array);

function B(array) {
  var index = array.indexOf(5);
  var arr = Array.from(array);
  arr.splice(index, 1)
  log('B', arr);

function C(array) {
  var index = array.indexOf(5);
  array.splice(index, 1);
  log('C', array);

function D(array) {
  var arr = array.filter(item => item !== 5)
  log('D', arr);

function E(array) {
  var index = array.indexOf(5);
  var arr = array.filter((item, i) => i !== index)
  log('E', arr);

function F(array) {
  var index = array.indexOf(5);
  var arr = array.slice(0, index).concat(array.slice(index + 1))
  log('F', arr);

function G(array) {
  var index = array.indexOf(5);
  var arr = [...array.slice(0, index), ...array.slice(index + 1)]
  log('G', arr);

function H(array) {
  var index = array.indexOf(5);
  var arr = array.slice(0);
  arr.splice(index, 1);
  log('H', arr);

This snippet only presents code used in performance tests - it does not perform tests itself.

Comparison for browsers: Chrome v78.0.0, Safari v13.0.4, and Firefox v71.0.0

Enter image description here

@Arun s 2019-12-27 10:58:34

You can use splice to remove objects or values from an array.

Let's consider an array of length 5, with values 10,20,30,40,50, and I want to remove the value 30 from it.

var array = [10,20,30,40,50];
if (array.indexOf(30) > -1) {
   array.splice(array.indexOf(30), 1);
console.log(array); // [10,20,40,50]

@Ravi Makwana 2020-01-09 09:54:49

I found this blog post which is showing nine ways to do it:

9 Ways to Remove Elements From A JavaScript Array - Plus How to Safely Clear JavaScript Arrays

I prefer to use filter():

var filtered_arr = arr.filter(function(ele){
   return ele != value;

@Daniel Waltrip 2020-01-23 02:09:59

This doesn't remove the item from the array. It creates a brand new array with some items from the original array filtered out.

@Ravi Makwana 2020-01-23 04:30:34

Yes it will return new array filtered. let me update code 2020-01-31 19:56:47

If the array contains duplicate values and you want to remove all the occurrences of your target then this is the way to go...

let data = [2, 5, 9, 2, 8, 5, 9, 5];
let target = 5;
data = data.filter(da => da !== target);

Note: - the filter doesn't change the original array; instead it creates a new array.

So assigning again is important.

That's led to another problem. You can't make the variable const. It should be let or var.

@Peter Olson 2011-04-23 22:20:56

I don't know how you are expecting array.remove(int) to behave. There are three possibilities I can think of that you might want.

To remove an element of an array at an index i:

array.splice(i, 1);

If you want to remove every element with value number from the array:

for(var i = array.length - 1; i >= 0; i--) {
    if(array[i] === number) {
        array.splice(i, 1);

If you just want to make the element at index i no longer exist, but you don't want the indexes of the other elements to change:

delete array[i];

@Ashish 2019-02-05 05:34:45

Splice, filter and delete to remove an element from an array

Every array has its index, and it helps to delete a particular element with their index.

The splice() method

array.splice(index, 1);    

The first parameter is index and the second is the number of elements you want to delete from that index.

So for a single element, we use 1.

The delete method

delete array[index]

The filter() method

If you want to delete an element which is repeated in an array then filter the array:

removeAll = array.filter(e => e != elem);

Where elem is the element you want to remove from the array and array is your array name.

@ujeenator 2013-12-19 19:54:26

Edited on 2016 October

  • Do it simple, intuitive and explicit (Occam's razor)
  • Do it immutable (original array stay unchanged)
  • Do it with standard JavaScript functions, if your browser doesn't support them - use polyfill

In this code example I use "array.filter(...)" function to remove unwanted items from an array. This function doesn't change the original array and creates a new one. If your browser doesn't support this function (e.g. Internet Explorer before version 9, or Firefox before version 1.5), consider using the filter polyfill from Mozilla.

Removing item (ECMA-262 Edition 5 code aka oldstyle JavaScript)

var value = 3

var arr = [1, 2, 3, 4, 5, 3]

arr = arr.filter(function(item) {
    return item !== value

// [ 1, 2, 4, 5 ]

Removing item (ECMAScript 6 code)

let value = 3

let arr = [1, 2, 3, 4, 5, 3]

arr = arr.filter(item => item !== value)

// [ 1, 2, 4, 5 ]

IMPORTANT ECMAScript 6 "() => {}" arrow function syntax is not supported in Internet Explorer at all, Chrome before 45 version, Firefox before 22 version, and Safari before 10 version. To use ECMAScript 6 syntax in old browsers you can use BabelJS.

Removing multiple items (ECMAScript 7 code)

An additional advantage of this method is that you can remove multiple items

let forDeletion = [2, 3, 5]

let arr = [1, 2, 3, 4, 5, 3]

arr = arr.filter(item => !forDeletion.includes(item))
// !!! Read below about array.includes(...) support !!!

// [ 1, 4 ]

IMPORTANT "array.includes(...)" function is not supported in Internet Explorer at all, Chrome before 47 version, Firefox before 43 version, Safari before 9 version, and Edge before 14 version so here is polyfill from Mozilla.

Removing multiple items (in the future, maybe)

If the "This-Binding Syntax" proposal is ever accepted, you'll be able to do this:

// array-lib.js

export function remove(...forDeletion) {
    return this.filter(item => !forDeletion.includes(item))

// main.js

import { remove } from './array-lib.js'

let arr = [1, 2, 3, 4, 5, 3]

// :: This-Binding Syntax Proposal
// using "remove" function as "virtual method"
// without extending Array.prototype
arr = arr::remove(2, 3, 5)

// [ 1, 4 ]

Try it yourself in BabelJS :)


@Abdennour TOUMI 2016-10-07 19:42:51

ES6 & without mutation: (October 2016)

const removeByIndex = (list, index) =>
        ...list.slice(0, index),
        ...list.slice(index + 1)
output = removeByIndex([33,22,11,44],1) //=> [33,11,44]

@user4642212 2020-04-07 18:30:04

Why not just use filter then? array.filter((_, index) => index !== removedIndex);.

@Abdennour TOUMI 2020-04-07 20:37:15

@user4642212 you are right! also, I liked the underscore of Golang style

@Janardan Prajapati 2020-01-28 12:04:34

You can use


@majid savalanpour 2020-06-14 09:47:06

Your code remove all elements after index. For remove 1 element at index 3 you can use Array.splice(index, 1).

@Josh 2019-12-19 09:05:46

Remove a specific element from an array can be done in one line with the filter option, and it's supported by all browsers:

function removeValueFromArray(array, value) {
    return array.filter(e => e != value)

I tested this function here:

@sairfan 2020-01-30 21:03:23

Not valid for all browsers

@Peter Mortensen 2020-03-08 17:25:17

Perhaps qualify "all browsers"?

@rajat44 2016-10-04 08:07:50

You can use ES6. For example to delete the value '3' in this case:

var array=['1','2','3','4','5','6']
var newArray = array.filter((value)=>value!='3');

Output :

["1", "2", "4", "5", "6"]

@Claudio Holanda 2017-03-16 15:27:40

This answer is nice because it creates a copy of the original array, instead of modifying the original directly.

@Chang 2019-01-27 19:45:05

Note: Array.prototype.filter is ECMAScript 5.1 (No IE8). for more specific solutions:

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