By Davey


2009-02-24 08:26:26 8 Comments

Last time I asked a similar question but that was about svn related versioning info. Now I am wondering how to query windows "File version" attribute about eg. a dll. I payed attention to wmi and win32file modules as well without success.

8 comments

@syntaxaire 2019-10-04 18:06:00

I found that the only cross-platform answer (using pefile) couldn't find the version string I was looking for, which is the one shown in the 'Details' tab of the 'View properties' of a .DLL file on Windows. However, this code, based on the dump_info() function in pefile, is able to find those attributes, which include original filename, copyright, company name, and file and product versions.

You may need to replace encoding with a different encoding if they are not encoded using UTF-8.

import pefile

PATH_TO_FILE = 'C:\...'
pe = pefile.PE(PATH_TO_FILE)

if hasattr(pe, 'VS_VERSIONINFO'):
    for idx in range(len(pe.VS_VERSIONINFO)):
        if hasattr(pe, 'FileInfo') and len(pe.FileInfo) > idx:
            for entry in pe.FileInfo[idx]:
                if hasattr(entry, 'StringTable'):
                    for st_entry in entry.StringTable:
                        for str_entry in sorted(list(st_entry.entries.items())):
                            print('{0}: {1}'.format(
                                str_entry[0].decode('utf-8', 'backslashreplace'),
                                str_entry[1].decode('utf-8', 'backslashreplace')))

@derflocki 2013-04-18 07:11:09

Here is a version that also works in non-Windows environments, using the pefile module:

import pefile

def LOWORD(dword):
    return dword & 0x0000ffff
def HIWORD(dword): 
    return dword >> 16
def get_product_version(path):

    pe = pefile.PE(path)
    #print PE.dump_info()

    ms = pe.VS_FIXEDFILEINFO.ProductVersionMS
    ls = pe.VS_FIXEDFILEINFO.ProductVersionLS
    return (HIWORD (ms), LOWORD (ms), HIWORD (ls), LOWORD (ls))


if __name__ == "__main__":
    import sys
    try:
        print "%d.%d.%d.%d" % get_product_version(sys.argv[1])
    except:
        print "Version info not available. Maybe the file is not a Windows executable"

@Steve 2015-10-14 08:48:34

I find this to the job perfectly, but it takes over 10s to do it on a 30mb exe :(

@Steve 2015-10-14 13:10:25

I figured out from the source that you can cut that 10s down to 1s/2s by parsing only the resources directory, woo!: pe = pefile.PE(path, fast_load=True) pe.parse_data_directories(directories=[pefile.DIRECTORY_ENTR‌​Y['IMAGE_DIRECTORY_E‌​NTRY_RESOURCE']])

@derflocki 2015-10-14 18:04:48

Nice! I wanted to suggest something like that.

@the_void 2010-02-22 10:06:42

You can use the pyWin32 module from https://github.com/mhammond/pywin32:

from win32com.client import Dispatch

ver_parser = Dispatch('Scripting.FileSystemObject')
info = ver_parser.GetFileVersion(path)

if info == 'No Version Information Available':
    info = None

@Dev.K. 2017-06-01 04:18:08

Is there any way I can get the file description as well ? I did not see any method in FileSystemObject which does that :(

@Suneelm 2018-01-11 09:10:20

Worked like a charm. Thank you !!

@BeHappy 2019-05-30 23:46:40

After hours of frustration and struggle with pywin32, looks like all I needed was this....Thank you

@isanae 2019-05-22 23:13:49

Here's a working version of marsh's answer, only using the standard library. Use it like get_version_string(file, "FileVersion").

from ctypes import *

# returns the requested version information from the given file
#
# `language` should be an 8-character string combining both the language and
# codepage (such as "040904b0"); if None, the first language in the translation
# table is used instead
#
def get_version_string(filename, what, language=None):
    # VerQueryValue() returns an array of that for VarFileInfo\Translation
    #
    class LANGANDCODEPAGE(Structure):
        _fields_ = [
            ("wLanguage", c_uint16),
            ("wCodePage", c_uint16)]

    wstr_file = wstring_at(filename)

    # getting the size in bytes of the file version info buffer
    size = windll.version.GetFileVersionInfoSizeW(wstr_file, None)
    if size == 0:
        raise WinError()

    buffer = create_string_buffer(size)

    # getting the file version info data
    if windll.version.GetFileVersionInfoW(wstr_file, None, size, buffer) == 0:
        raise WinError()

    # VerQueryValue() wants a pointer to a void* and DWORD; used both for
    # getting the default language (if necessary) and getting the actual data
    # below
    value = c_void_p(0)
    value_size = c_uint(0)

    if language is None:
        # file version information can contain much more than the version
        # number (copyright, application name, etc.) and these are all
        # translatable
        #
        # the following arbitrarily gets the first language and codepage from
        # the list
        ret = windll.version.VerQueryValueW(
            buffer, wstring_at(r"\VarFileInfo\Translation"),
            byref(value), byref(value_size))

        if ret == 0:
            raise WinError()

        # value points to a byte inside buffer, value_size is the size in bytes
        # of that particular section

        # casting the void* to a LANGANDCODEPAGE*
        lcp = cast(value, POINTER(LANGANDCODEPAGE))

        # formatting language and codepage to something like "040904b0"
        language = "{0:04x}{1:04x}".format(
            lcp.contents.wLanguage, lcp.contents.wCodePage)

    # getting the actual data
    res = windll.version.VerQueryValueW(
        buffer, wstring_at("\\StringFileInfo\\" + language + "\\" + what),
        byref(value), byref(value_size))

    if res == 0:
        raise WinError()

    # value points to a string of value_size characters, minus one for the
    # terminating null
    return wstring_at(value.value, value_size.value - 1)

@Erik Šťastný 2019-06-13 08:44:21

At return you can pass (value_size.value -1) because now you get one null character at the end of string.

@marsh 2016-08-12 18:58:24

Here is a version that does not require any additional libraries. I could not use win32api like everyone had suggested:

From: https://mail.python.org/pipermail//python-list/2006-November/402797.html

Only copied here in case the original goes missing.

import array
from ctypes import *

def get_file_info(filename, info):
    """
    Extract information from a file.
    """
    # Get size needed for buffer (0 if no info)
    size = windll.version.GetFileVersionInfoSizeA(filename, None)
    # If no info in file -> empty string
    if not size:
        return ''
    # Create buffer
    res = create_string_buffer(size)
    # Load file informations into buffer res
    windll.version.GetFileVersionInfoA(filename, None, size, res)
    r = c_uint()
    l = c_uint()
    # Look for codepages
    windll.version.VerQueryValueA(res, '\\VarFileInfo\\Translation',
                                  byref(r), byref(l))
    # If no codepage -> empty string
    if not l.value:
        return ''
    # Take the first codepage (what else ?)
    codepages = array.array('H', string_at(r.value, l.value))
    codepage = tuple(codepages[:2].tolist())
    # Extract information
    windll.version.VerQueryValueA(res, ('\\StringFileInfo\\%04x%04x\\'
+ info) % codepage,
                                        byref(r), byref(l))
    return string_at(r.value, l.value)

Used like so:

   print get_file_info(r'C:\WINDOWS\system32\calc.exe', 'FileVersion')

@ewerybody 2017-11-06 19:28:52

WindowsError: exception: access violation reading 0x0000000082E47858 when getting the codepages. string_at(r.value, l.value) fails there :(

@Helmut N. 2011-11-03 10:08:02

Here is a function which reads all file attributes as a dictionary:

import win32api

#==============================================================================
def getFileProperties(fname):
#==============================================================================
    """
    Read all properties of the given file return them as a dictionary.
    """
    propNames = ('Comments', 'InternalName', 'ProductName',
        'CompanyName', 'LegalCopyright', 'ProductVersion',
        'FileDescription', 'LegalTrademarks', 'PrivateBuild',
        'FileVersion', 'OriginalFilename', 'SpecialBuild')

    props = {'FixedFileInfo': None, 'StringFileInfo': None, 'FileVersion': None}

    try:
        # backslash as parm returns dictionary of numeric info corresponding to VS_FIXEDFILEINFO struc
        fixedInfo = win32api.GetFileVersionInfo(fname, '\\')
        props['FixedFileInfo'] = fixedInfo
        props['FileVersion'] = "%d.%d.%d.%d" % (fixedInfo['FileVersionMS'] / 65536,
                fixedInfo['FileVersionMS'] % 65536, fixedInfo['FileVersionLS'] / 65536,
                fixedInfo['FileVersionLS'] % 65536)

        # \VarFileInfo\Translation returns list of available (language, codepage)
        # pairs that can be used to retreive string info. We are using only the first pair.
        lang, codepage = win32api.GetFileVersionInfo(fname, '\\VarFileInfo\\Translation')[0]

        # any other must be of the form \StringfileInfo\%04X%04X\parm_name, middle
        # two are language/codepage pair returned from above

        strInfo = {}
        for propName in propNames:
            strInfoPath = u'\\StringFileInfo\\%04X%04X\\%s' % (lang, codepage, propName)
            ## print str_info
            strInfo[propName] = win32api.GetFileVersionInfo(fname, strInfoPath)

        props['StringFileInfo'] = strInfo
    except:
        pass

    return props

@iridescent 2015-01-01 13:09:02

Wow, great work. How did you even find out the StringFileInfo stuff.. that's what I need. thanks a lot.

@theannouncer 2016-08-08 19:40:05

For those who care, 65536 is half a DWORD (2 **16)

@Jamie 2009-08-06 08:34:19

Better to add a try/except in case the file has no version number attribute.

filever.py


from win32api import GetFileVersionInfo, LOWORD, HIWORD

def get_version_number (filename):
    try:
        info = GetFileVersionInfo (filename, "\\")
        ms = info['FileVersionMS']
        ls = info['FileVersionLS']
        return HIWORD (ms), LOWORD (ms), HIWORD (ls), LOWORD (ls)
    except:
        return 0,0,0,0

if __name__ == '__main__':
  import os
  filename = os.environ["COMSPEC"]
  print ".".join ([str (i) for i in get_version_number (filename)])

yourscript.py:


import os,filever

myPath="C:\\path\\to\\check"

for root, dirs, files in os.walk(myPath):
    for file in files:
        file = file.lower() # Convert .EXE to .exe so next line works
        if (file.count('.exe') or file.count('.dll')): # Check only exe or dll files
            fullPathToFile=os.path.join(root,file)
            major,minor,subminor,revision=filever.get_version_number(fullPathToFile)
            print "Filename: %s \t Version: %s.%s.%s.%s" % (file,major,minor,subminor,revision)

Cheers!

@Davey 2009-02-27 13:40:42

I found this solution at "timgolden" site. Works fine.

from win32api import GetFileVersionInfo, LOWORD, HIWORD

def get_version_number (filename):
  info = GetFileVersionInfo (filename, "\\")
  ms = info['FileVersionMS']
  ls = info['FileVersionLS']
  return HIWORD (ms), LOWORD (ms), HIWORD (ls), LOWORD (ls)

if __name__ == '__main__':
  import os
  filename = os.environ["COMSPEC"]
  print ".".join ([str (i) for i in get_version_number (filename)])

Related Questions

Sponsored Content

63 Answered Questions

[SOLVED] Calling an external command from Python

23 Answered Questions

[SOLVED] Does Python have a ternary conditional operator?

16 Answered Questions

[SOLVED] What are metaclasses in Python?

37 Answered Questions

[SOLVED] How do I check whether a file exists without exceptions?

36 Answered Questions

[SOLVED] How to install pip on Windows?

10 Answered Questions

[SOLVED] Does Python have a string 'contains' substring method?

16 Answered Questions

[SOLVED] How do I copy a file in Python?

21 Answered Questions

[SOLVED] How do I list all files of a directory?

  • 2010-07-08 19:31:22
  • duhhunjonn
  • 3783939 View
  • 3474 Score
  • 21 Answer
  • Tags:   python directory

24 Answered Questions

[SOLVED] Is there an equivalent of 'which' on the Windows command line?

19 Answered Questions

[SOLVED] Python progression path - From apprentice to guru

  • 2010-04-04 00:28:33
  • Morlock
  • 360998 View
  • 659 Score
  • 19 Answer
  • Tags:   python

Sponsored Content