By thugsb


2011-09-09 15:42:29 8 Comments

I've got an array:

myArray = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}, etc.]

I'm unable to change the structure of the array. I'm being passed an id of 45, and I want to get 'bar' for that object in the array.

How do I do this in JavaScript or using jQuery?

30 comments

@Kamil Kiełczewski 2020-06-20 22:52:28

Performance

Today 2020.06.20 I perform test on MacOs High Sierra on Chrome 81.0, Firefox 77.0 and Safari 13.1 for chosen solutions.

Conclusions for solutions which use precalculations

Solutions with precalculations (K,L) are (much much) faster than other solutions and will not be compared with them - probably they are use some special build-in browser optimisations

  • surprisingly on Chrome and Safari solution based on Map (K) are much faster than solution based on object {} (L)
  • surprisingly on Safari for small arrays solution based on object {} (L) is slower than traditional for (E)
  • surprisingly on Firefox for small arrays solution based on Map (K) is slower than traditional for (E)

Conclusions when searched objects ALWAYS exists

  • solution which use traditional for (E) is fastest for small arrays and fast for big arrays
  • solution using cache (J) is fastest for big arrays - surprisingly for small arrays is medium fast
  • solutions based on find (A) and findIndex (B) are fast for small arras and medium fast on big arrays
  • solution based on $.map (H) is slowest on small arrays
  • solution based on reduce (D) is slowest on big arrays

enter image description here

Conclusions when searched objects NEVER exists

  • solution based on traditional for (E) is fastest on small and big arrays (except Chrome-small arrays where it is second fast)
  • solution based on reduce (D) is slowest on big arrays
  • solution which use cache (J) is medium fast but can be speed up if we save in cache also keys which have null values (which was not done here because we want to avoid unlimited memory consumption in cache in case when many not existing keys will be searched)

enter image description here

Details

For solutions

  • without precalculations: A B C D E F G H I J (the J solution use 'inner' cache and it speed depend on how often searched elements will repeat)
  • with precalculations K L

I perform four tests. In tests I want to find 5 objects in 10 loop iterations (the objects ID not change during iterations) - so I call tested method 50 times but only first 5 times have unique id values:

  • small array (10 elements) and searched object ALWAYS exists - you can perform it HERE
  • big array (10k elements) and searched object ALWAYS exist - you can perform it HERE
  • small array (10 elements) and searched object NEVER exists - you can perform it HERE
  • big array (10k elements) and searched object NEVER exists - you can perform it HERE

Tested codes are presented below

function A(arr, id) {
  return arr.find(o=> o.id==id);
}

function B(arr, id) {
  let idx= arr.findIndex(o=> o.id==id);
  return arr[idx];
}

function C(arr, id) {
  return arr.filter(o=> o.id==id)[0];
}

function D(arr, id) {
  return arr.reduce((a, b) => (a.id==id && a) || (b.id == id && b));
}

function E(arr, id) {
  for (var i = 0; i < arr.length; i++) if (arr[i].id==id) return arr[i];
  return null;
}

function F(arr, id) {
  var retObj ={};
  $.each(arr, (index, obj) => {
    if (obj.id == id) { 
      retObj = obj;
      return false;
    }
  });
  return retObj;
}

function G(arr, id) {
  return $.grep(arr, e=> e.id == id )[0];
}

function H(arr, id) {
  return $.map(myArray, function(val) {
    return val.id == id ? val : null;
  })[0];
}

function I(arr, id) {
  return _.find(arr, o => o.id==id);
}

let J = (()=>{
  let cache = new Map();
  return function J(arr,id,el=null) { 
    return cache.get(id) || (el=arr.find(o=> o.id==id), cache.set(id,el), el);
  }
})();

function K(arr, id) {
  return mapK.get(id)
}

function L(arr, id) {
  return mapL[id];
}



// -------------
// TEST
// -------------

console.log('Find id=5');

myArray = [...Array(10)].map((x,i)=> ({'id':`${i}`, 'foo':`bar_${i}`}));
const mapK = new Map( myArray.map(el => [el.id, el]) );
const mapL = {}; myArray.forEach(el => mapL[el.id]=el);



[A,B,C,D,E,F,G,H,I,J,K,L].forEach(f=> console.log(`${f.name}: ${JSON.stringify(f(myArray, '5'))}`));

console.log('Whole array',JSON.stringify(myArray));
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>

This snippet only presents tested codes

Example tests results for Chrome for small array where searched objects always exists

enter image description here

@Kamil Kiełczewski 2020-06-17 23:29:42

Dynamic cached find

In this solution, when we search for some object, we save it in cache. This is middle point between "always search solutions" and "create hash-map for each object in precalculations".

let cachedFind = (()=>{
  let cache = new Map();
  return (arr,id,el=null) => 
    cache.get(id) || (el=arr.find(o=> o.id==id), cache.set(id,el), el);
})();


// ---------
// TEST
// ---------

let myArray = [...Array(100000)].map((x,i)=> ({'id':`${i}`, 'foo':`bar_${i}`}));

// example usage

console.log( cachedFind(myArray,'1234').foo );





// Benchmark

let bench = (id) => {
  console.time   ('time for '+id ); 
  console.log    ( cachedFind(myArray,id).foo );  // FIND
  console.timeEnd('time for '+id );
}

console.log('----- no cached -----');
bench(50000);
bench(79980);
bench(99990);
console.log('-----  cached   -----');
bench(79980); // cached
bench(99990); // cached

@Nick Parsons 2020-06-13 11:20:20

As others have pointed out, .find() is the way to go when looking for one object within your array. However, if your object cannot be found using this method, your program will crash:

const myArray = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}];
const res = myArray.find(x => x.id === '100').foo; // Uh oh!
/*
Error:
"Uncaught TypeError: Cannot read property 'foo' of undefined"
*/

This can be fixed by checking whether the result of .find() is defined before using using .foo on it. Modern JS allows us to do this easily with optional chaining, returning undefined if the object cannot be found, rather than crashing your code:

const myArray = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}];
const res = myArray.find(x => x.id === '100')?.foo; // No error!
console.log(res); // undefined when the object cannot be found

@TLbiz 2018-09-25 06:49:04

We can use Jquery methods $.each()/$.grep()

var data= [];
$.each(array,function(i){if(n !== 5 && i > 4){data.push(item)}}

or

var data = $.grep(array, function( n, i ) {
  return ( n !== 5 && i > 4 );
});

use ES6 syntax:

Array.find, Array.filter, Array.forEach, Array.map

Or use Lodash https://lodash.com/docs/4.17.10#filter, Underscore https://underscorejs.org/#filter

@maheshwaghmare 2019-07-25 10:05:16

Recently, I have to face the same thing in which I need to search the string from a huge array.

After some search I found It'll be easy to handle with simple code:

Code:

var items = mydata.filter(function(item){
    return item.word.toLowerCase().startsWith( 'gk );
})

See https://jsfiddle.net/maheshwaghmare/cfx3p40v/4/

Serach from 20k strings

@Guffa 2011-09-09 15:54:31

As you are already using jQuery, you can use the grep function which is intended for searching an array:

var result = $.grep(myArray, function(e){ return e.id == id; });

The result is an array with the items found. If you know that the object is always there and that it only occurs once, you can just use result[0].foo to get the value. Otherwise you should check the length of the resulting array. Example:

if (result.length === 0) {
  // no result found
} else if (result.length === 1) {
  // property found, access the foo property using result[0].foo
} else {
  // multiple items found
}

@Vicky Chijwani 2012-12-11 12:03:01

It'd be safer to use === instead of ==, to avoid weird issues with JavaScript's == operator.

@Guffa 2012-12-11 12:17:43

@VickyChijwani: Are there any issues when comparing a string to a string?

@Vicky Chijwani 2012-12-11 13:19:25

Well, if you're absolutely sure that both e.id and id will be strings, I suppose it's ok to use ==. But if you're not sure, you might face problems (since '' == 0 is true but '' === 0 is false). Not to mention === seems to be faster (stackoverflow.com/questions/359494/…).

@Vicky Chijwani 2012-12-11 13:27:48

Basically I always use === because it works exactly like == in other programming languages. I consider == to be non-existent in JavaScript.

@tne 2014-03-12 11:41:55

@de. Many answers here provide the intended behavior when looking up unique values; you can essentially recognize them by the fact that they return or break from their loop early (or instruct a lower-level construct to stop iterating). See JaredPar's answer for a canonical example, and Aaronius's comment on that answer for the same insight. In general, people differentiate between "filter" and "find" functions in this way, but terminology varies. Though more efficient, this is still a linear search, so if you want to use a hash table, see Aaron Digulla's answer (beware of impl. details).

@Guffa 2014-03-12 13:02:07

@tne: Note that there is nothing in the question that specifically says that the id is unique, and that my answer doesn't do that assumption.

@tne 2014-03-12 13:23:27

@Guffa: Indeed, your answer is absolutely correct with regard to the question as it is stated -- I just felt like pointing it out since it'll likely concern many readers who might otherwise miss an opportunity to do the right thing when they can (when the search property contains unique values).

@stevenspiel 2014-10-23 14:25:42

once you have result, just do myArray.pop(result)

@Guffa 2014-10-23 17:15:23

@mr.musicman: What are you trying to accomplish with that? The pop method doesn't take a parameter, so it will just remove the last item from the array and return it.

@Guffa 2015-01-07 09:03:34

@MatíasFidemraizer: The filter method is not supported in older browsers like IE 8, so using a library like jQuery is still a good option if you need it to work for as many as possible.

@Matías Fidemraizer 2015-01-07 09:05:55

@Guffa Who cares about IE8 now. It's an edge case. Since you're answer is the selected as right one, a lot of novice JS devs won't know about filter because of your answer! You've a lot of responsibility :D

@Guffa 2015-01-07 12:08:09

@MatíasFidemraizer: This answer doesn't try to list all possible solutions, it only shows the simplest and most compatible solution in the situation specified in the question. IE 8 is still too common for advocating a solution that doesn't support it, when there is a solution that is as simple and does support it.

@patotoma 2017-09-24 17:41:36

I've created a tiny utility just for this where you can access with O(1) called super-array

@Vu Truong 2016-05-24 02:28:59

My way to find index of array:

index = myArray.map((i) => i.id).indexOf(value_of_id);
item = myArray[index];

@Michał Perłakowski 2016-02-14 21:11:10

Use the find() method:

myArray.find(x => x.id === '45').foo;

From MDN:

The find() method returns the first value in the array, if an element in the array satisfies the provided testing function. Otherwise undefined is returned.


If you want to find its index instead, use findIndex():

myArray.findIndex(x => x.id === '45');

From MDN:

The findIndex() method returns the index of the first element in the array that satisfies the provided testing function. Otherwise -1 is returned.


If you want to get an array of matching elements, use the filter() method instead:

myArray.filter(x => x.id === '45');

This will return an array of objects. If you want to get an array of foo properties, you can do this with the map() method:

myArray.filter(x => x.id === '45').map(x => x.foo);

Side note: methods like find() or filter(), and arrow functions are not supported by older browsers (like IE), so if you want to support these browsers, you should transpile your code using Babel (with the polyfill).

@Apqu 2016-10-20 10:33:02

For multiple testing conditions would it therefore be something like: myArray.find(x => x.id === '45' && x.color == 'red').foo

@Canta 2017-11-13 17:38:03

For me, best answer so far. Doesn't need jQuery neither creating new auxiliar arrays.

@Govinda Rajbhar 2018-05-30 13:13:31

myArray.find(x => x.id === '45') it does not work on mac PC

@Michał Perłakowski 2018-06-04 17:50:35

@T.J.Crowder I don't think that it's a good idea to copy-paste polyfills from MDN into your code; instead, you should use npm packages with polyfills. And Babel does include polyfills for ES2015+ features, in the babel-polyfill package.

@T.J. Crowder 2018-06-04 18:23:18

@MichałPerłakowski - I did say "(Babel can also include polyfills for some things)" And agreed, polyfilling has moved on since copy-and-paste from MDN. :-)

@ColinWa 2018-10-01 09:22:08

This example uses ECMAScript 6 arrow function. In case of errors when using arrow functions, there are other ways out. See (developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…‌​) and (dmitripavlutin.com/…)

@Leland 2019-03-14 16:54:40

filter actually has support back to IE9!

@Frazer Kirkman 2019-04-10 17:34:57

myArray.find(x => x.id === '45').foo; throws an exception if there is no object with an id of '45'.

@Savan Kaneriya 2018-12-12 06:35:58

More generic and short

function findFromArray(array,key,value) {
        return array.filter(function (element) {
            return element[key] == value;
        }).shift();
}

in your case Ex. var element = findFromArray(myArray,'id',45) that will give you the whole element.

@Jonas Wilms 2017-08-08 15:26:35

If you do this multiple times, you may set up a Map (ES6):

const map = new Map( myArray.map(el => [el.id, el]) );

Then you can simply do:

map.get(27).foo

@Rúnar Berg 2014-02-10 22:32:16

ECMAScript 2015 provides the find() method on arrays:

var myArray = [
 {id:1, name:"bob"},
 {id:2, name:"dan"},
 {id:3, name:"barb"},
]

// grab the Array item which matchs the id "2"
var item = myArray.find(item => item.id === 2);

// print
console.log(item.name);

It works without external libraries. But if you want older browser support you might want to include this polyfill.

@lejonl 2014-02-19 22:57:09

Probably cause it still seems very experimental and not many browsers support it, developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

@Shaggy 2017-03-06 11:29:30

This can be simplified to myArray.find(d=>d.id===45).foo;.

@Rúnar Berg 2017-03-06 19:49:23

@Shaggy or even myArray.find(({ id }) => id === 45).foo. But this is an old answer that was written before ES2015 syntax was as well supported as now. @Gothdo’s answer is currently the most up to date in the thread.

@Herbert Peters 2018-04-03 00:57:08

@Shaggy if the .find() returns undefined, then your optimization throws an error. So this solution is can be used only in cases where a match is guaranteed.

@Rúnar Berg 2018-04-03 20:14:54

@HerbertPeters If you want to be sure you can alway null-check, which will be really easy with optional chaining: myArray.find(d => d.id === 45)?.foo.

@Milad Rashidi 2018-08-14 06:16:54

This solution is for ES6 and it doesn't compatible with IE browser.

@Rúnar Berg 2018-08-16 20:25:43

@MiladRashidi Like the answer states there is a polyfill if you want older browser support. Likewise it is easy to rewrite using the older syntax.

@Sumit Ridhal 2017-05-02 15:40:32

Use Array.prototype.filter() function.

DEMO: https://jsfiddle.net/sumitridhal/r0cz0w5o/4/

JSON

var jsonObj =[
 {
  "name": "Me",
  "info": {
   "age": "15",
   "favColor": "Green",
   "pets": true
  }
 },
 {
  "name": "Alex",
  "info": {
   "age": "16",
   "favColor": "orange",
   "pets": false
  }
 },
{
  "name": "Kyle",
  "info": {
   "age": "15",
   "favColor": "Blue",
   "pets": false
  }
 }
];

FILTER

var getPerson = function(name){
    return jsonObj.filter(function(obj) {
      return obj.name === name;
    });
}

@Valay 2017-06-14 21:22:01

how can I search within nested object ? Like pets= false should return two objects.

@Sumit Ridhal 2017-06-17 18:07:58

use .filter method on obj.info in nested loop. var getPerson = function(name){ return jsonObj.filter(function(obj) { return obj.info.filter(function(info) { return pets === false; }); }); }

@DagicCross 2018-06-08 02:10:57

you could use es6 style too imo... const filterData = jsonObj.filter(obj => obj.name === 'Alex')

@Dan W 2015-02-28 18:04:18

Here's how I'd go about it in pure JavaScript, in the most minimal manner I can think of that works in ECMAScript 3 or later. It returns as soon as a match is found.

var getKeyValueById = function(array, key, id) {
    var testArray = array.slice(), test;
    while(test = testArray.pop()) {
        if (test.id === id) {
            return test[key];
        }
    }
    // return undefined if no matching id is found in array
    return;
}

var myArray = [{'id':'73', 'foo':'bar'}, {'id':'45', 'foo':'bar'}]
var result = getKeyValueById(myArray, 'foo', '45');

// result is 'bar', obtained from object with id of '45'

@Tom 2016-03-23 10:24:18

While there are many correct answers here, many of them do not address the fact that this is an unnecessarily expensive operation if done more than once. In an extreme case this could be the cause of real performance problems.

In the real world, if you are processing a lot of items and performance is a concern it's much faster to initially build a lookup:

var items = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}];

var lookup = items.reduce((o,i)=>o[i.id]=o,{});

you can then get at items in fixed time like this :

var bar = o[id];

You might also consider using a Map instead of an object as the lookup: https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Map

@kaizer1v 2014-10-26 04:39:55

You can do this even in pure JavaScript by using the in built "filter" function for arrays:

Array.prototype.filterObjects = function(key, value) {
    return this.filter(function(x) { return x[key] === value; })
}

So now simply pass "id" in place of key and "45" in place of value, and you will get the full object matching an id of 45. So that would be,

myArr.filterObjects("id", "45");

@Michał Perłakowski 2016-02-14 21:15:02

Don't modify objects you don't own.

@pimvdb 2011-09-09 15:46:33

I think the easiest way would be the following, but it won't work on Internet Explorer 8 (or earlier):

var result = myArray.filter(function(v) {
    return v.id === '45'; // Filter out the appropriate one
})[0].foo; // Get result and access the foo property

@Igor Zinov'yev 2011-09-09 15:47:38

I'm curious, is there any performance advantage here compared to the usual for?

@pimvdb 2011-09-09 15:48:50

@Igor Zinov'yev: Yes, there certainly are performance impacts with those ES5 array tools. A separate function is executed for each element, so it won't be really fast compared to a direct for loop.

@Igor Zinov'yev 2011-09-09 15:50:36

So you're saying that it would be slower? Also, it will always scan the whole array, as far as I can see, whereas the for loop will terminate on the first match.

@Adam Grant 2013-07-17 21:12:29

If you need support for IE8, just drop this in: stackoverflow.com/questions/7153470/…

@Stan 2017-02-23 14:57:44

This code will throw an error if there's no element with that id

@stevenspiel 2014-10-23 14:23:27

Building on the accepted answer:

jQuery:

var foo = $.grep(myArray, function(e){ return e.id === foo_id})
myArray.pop(foo)

Or CoffeeScript:

foo = $.grep myArray, (e) -> e.id == foo_id
myArray.pop foo

@soytian 2014-10-22 09:15:19

This solution may helpful as well:

Array.prototype.grep = function (key, value) {
    var that = this, ret = [];
    this.forEach(function (elem, index) {
        if (elem[key] === value) {
            ret.push(that[index]);
        }
    });
    return ret.length < 2 ? ret[0] : ret;
};
var bar = myArray.grep("id","45");

I made it just like $.grep and if one object is find out, function will return the object, rather than an array.

@Michał Perłakowski 2016-02-14 21:15:29

Don't modify objects you don't own.

@soytian 2016-02-15 03:55:41

@Gothdo I Agree. If someone didn't know function will return the object, rather than an array may get a mistake, but I think it depends on users.

@aggaton 2014-04-08 17:14:19

As long as the browser supports ECMA-262, 5th edition (December 2009), this should work, almost one-liner:

var bFound = myArray.some(function (obj) {
    return obj.id === 45;
});

@MaxArt 2014-09-02 12:29:56

Almost. bFound is just a boolean that is true iff an element satisfies the required condition.

@volumexxx 2013-02-28 15:03:27

Use:

var retObj ={};
$.each(ArrayOfObjects, function (index, obj) {

        if (obj.id === '5') { // id.toString() if it is int

            retObj = obj;
            return false;
        }
    });
return retObj;

It should return an object by id.

@marcel 2014-04-08 06:53:52

you could shorten your code by using return obj.id === 5 ? obj : false; I use $.each a lot for iterating over arrays.

@Guffa 2015-04-05 19:43:34

@marcel: That won't work. As returning false will end the loop, it would only find the object if it was the first item in the array.

@deepflame 2012-11-06 08:52:01

You may try out Sugarjs from http://sugarjs.com/.

It has a very sweet method on Arrays, .find. So you can find an element like this:

array.find( {id: 75} );

You may also pass an object with more properties to it to add another "where-clause".

Note that Sugarjs extends native objects, and some people consider this very evil...

@MaxArt 2014-09-05 14:21:10

Well, it is evil, since it may happen that new EcmaScript versions may introduce new methods with the same name. And guess what, this is exactly what happened with find. My suggestion is that if you want to extend native prototypes, always use more specific names, leaving the simplest ones to future standard developments.

@deepflame 2014-09-22 12:19:19

this comment is nearly 2 years old and today I would rather use lodash anyways. However if you want you can read about this topic on the sugarjs website. They take a good stand to your opinion: sugarjs.com/native

@Tobias Beuving 2015-02-22 14:41:32

The op did specifically ask for a javascript or jquery solution

@hunter 2011-09-09 15:46:35

You can get this easily using the map() function:

myArray = [{'id':'73','foo':'bar'},{'id':'45','foo':'bar'}];

var found = $.map(myArray, function(val) {
    return val.id == 45 ? val.foo : null;
});

//found[0] == "bar";

Working example: http://jsfiddle.net/hunter/Pxaua/

@MaxArt 2014-09-05 14:30:17

I forgot about the fact that jQuery's map automatically removes null elements. It sounds misleading to me and to the common concept of map, as the result is not of the same length of the original collection.

@Zirak 2011-09-09 15:46:34

Iterate over any item in the array. For every item you visit, check that item's id. If it's a match, return it.

If you just want teh codez:

function getId(array, id) {
    for (var i = 0, len = array.length; i < len; i++) {
        if (array[i].id === id) {
            return array[i];
        }
    }
    return null; // Nothing found
}

And the same thing using ECMAScript 5's Array methods:

function getId(array, id) {
    var obj = array.filter(function (val) {
        return val.id === id;
    });

    // Filter returns an array, and we just want the matching item.
    return obj[0];
}

@laggingreflex 2015-06-04 00:13:49

Using native Array.reduce

var array = [ {'id':'73' ,'foo':'bar'} , {'id':'45' ,'foo':'bar'} , ];
var id = 73;
var found = array.reduce(function(a, b){
    return (a.id==id && a) || (b.id == id && b)
});

returns the object element if found, otherwise false

@Burn_E99 2016-03-09 23:29:40

Just a note, Array.reduce is not supported in IE8 and under.

@Danilo Colasso 2015-04-16 17:31:49

myArray.filter(function(a){ return a.id == some_id_you_want })[0]

@Justin 2015-08-21 18:00:21

@Valay 2017-06-14 21:25:37

@Danilo how can I search within nested object ? stackoverflow.com/questions/44550439/…

@ramya 2015-03-04 06:06:06

Consider "axesOptions" to be array of objects with an object format being {:field_type => 2, :fields => [1,3,4]}

function getFieldOptions(axesOptions,choice){
  var fields=[]
  axesOptions.each(function(item){
    if(item.field_type == choice)
        fields= hashToArray(item.fields)
  });
  return fields;
}

@Manu 2015-01-03 03:52:31

Shortest,

var theAnswerObj = _.findWhere(array, {id : 42});

@Tobias Beuving 2015-02-22 14:36:25

This requires using the underscore library, the OP asked for a plain javascript or jQuery solution

@Tim Ogilvy 2015-04-17 18:02:17

once you include underscore, this is not a short answer!

@quincyaft 2014-11-19 03:55:57

I really liked the answer provided by Aaron Digulla but needed to keep my array of objects so I could iterate through it later. So I modified it to

	var indexer = {};
	for (var i = 0; i < array.length; i++) {
	    indexer[array[i].id] = parseInt(i);
	}
	
	//Then you can access object properties in your array using 
	array[indexer[id]].property

@aleha 2016-09-25 17:30:16

Used same solution as fastest for finding items in array. But parseInt is redundant here.

@MaxArt 2014-09-02 12:41:43

Starting from aggaton's answer, this is a function that actually returns the wanted element (or null if not found), given the array and a callback function that returns a truthy value for the "correct" element:

function findElement(array, callback) {
    var elem;
    return array.some(function(e) {
        if (callback(e)) {
            elem = e;
            return true;
        }
    }) ? elem : null;
});

Just remember that this doesn't natively work on IE8-, as it doesn't support some. A polyfill can be provided, alternatively there's always the classic for loop:

function findElement(array, callback) {
    for (var i = 0; i < array.length; i++)
        if (callback(array[i])) return array[i];
    return null;
});

It's actually faster and more compact. But if you don't want to reinvent the wheel, I suggest using an utility library like underscore or lodash.

@Joe Lewis 2013-09-13 09:43:20

You can use filters,

  function getById(id, myArray) {
    return myArray.filter(function(obj) {
      if(obj.id == id) {
        return obj 
      }
    })[0]
  }

get_my_obj = getById(73, myArray);

@Adrian Lynch 2015-10-07 20:19:19

@TobiasBeuving - The one using Array.find() is plain JS too and should stop on the first find so will be more efficient.

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